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ahoymewmewBest ResponseYou've already chosen the best response.0
These are the problems. V
 one year ago

wioBest ResponseYou've already chosen the best response.1
Where are you stuck? Do you know: \[\sqrt{a}\times \sqrt{b} = \sqrt{a\times b}\]
 one year ago

ahoymewmewBest ResponseYou've already chosen the best response.0
no @wio its confusing me.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Multiply the numbers that are outside the radicals together, then multiply the numbers inside the radicals together. If the new radicand can be simplified by extracting roots, then do that and multiply those roots by the numbers outside.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
#3 as an example: \[7xy \sqrt{2x} \cdot 3\sqrt{4xy^2} \rightarrow (7xy)(3) \cdot \sqrt{(2x)(4xy^2)}\]
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
\[(7xy)(3) \cdot \sqrt{(2x)(4xy^2)} = 21xy \cdot \sqrt{2 \cdot 4 \cdot x^2 \cdot y^2}\] The radical contains the squares, 4, x^2, and y^2, so take the roots of those out. \[21xy \cdot 2 \cdot x \cdot y \sqrt{2}\] Then just simplify that the rest of the way.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Also note that you could have simplified the second radical first by taking out the 2 and the y since it had 4y^2 as a perfect square already.
 one year ago
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