A community for students.
Here's the question you clicked on:
 0 viewing
ahoymewmew
 2 years ago
Can someone help me with Multiplying Radicals?
ahoymewmew
 2 years ago
Can someone help me with Multiplying Radicals?

This Question is Closed

ahoymewmew
 2 years ago
Best ResponseYou've already chosen the best response.0These are the problems. V

wio
 2 years ago
Best ResponseYou've already chosen the best response.1Where are you stuck? Do you know: \[\sqrt{a}\times \sqrt{b} = \sqrt{a\times b}\]

ahoymewmew
 2 years ago
Best ResponseYou've already chosen the best response.0no @wio its confusing me.

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.1Multiply the numbers that are outside the radicals together, then multiply the numbers inside the radicals together. If the new radicand can be simplified by extracting roots, then do that and multiply those roots by the numbers outside.

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.1#3 as an example: \[7xy \sqrt{2x} \cdot 3\sqrt{4xy^2} \rightarrow (7xy)(3) \cdot \sqrt{(2x)(4xy^2)}\]

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.1\[(7xy)(3) \cdot \sqrt{(2x)(4xy^2)} = 21xy \cdot \sqrt{2 \cdot 4 \cdot x^2 \cdot y^2}\] The radical contains the squares, 4, x^2, and y^2, so take the roots of those out. \[21xy \cdot 2 \cdot x \cdot y \sqrt{2}\] Then just simplify that the rest of the way.

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.1Also note that you could have simplified the second radical first by taking out the 2 and the y since it had 4y^2 as a perfect square already.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.