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 2 years ago
Prove that the range of \[1 + \sin ^{2} x\] is between 1 and 2, inclusive.
How do I show this?
 2 years ago
Prove that the range of \[1 + \sin ^{2} x\] is between 1 and 2, inclusive. How do I show this?

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AravindG
 2 years ago
Best ResponseYou've already chosen the best response.3sin x maximum vallue is 1

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.3so max value of exp will be 2

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.3now minimum value when x=0 sin x=0

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.3so 1+x^2 has values [1,2]

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.3becaus sin x max value is 1

akash_809
 2 years ago
Best ResponseYou've already chosen the best response.0sinx , minimum value =1, sin^2x , minimum value =0 ( sin^2x) cant be negative and maximum value of sin^2x=1....put sin^2x=1 for maximum value and put sin^2x=0 for minimum value

akash_809
 2 years ago
Best ResponseYou've already chosen the best response.0yes maximum value is 2

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.3so to maximise sin^x+1 ,,,,sin x maximum should be there
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