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amistre64 Group TitleBest ResponseYou've already chosen the best response.0
what methods do you know of?
 2 years ago

haganmc Group TitleBest ResponseYou've already chosen the best response.0
undetermined coefficients
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
got a lousy connection i believe
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
happening to me too, OS is bugged today.
 2 years ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
site is slow for me too :(
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
well, lets start by dividing off that 2 x' + x/2 = 3t^2/2 we want to determine an e^rt that will allow us to turn this into a product rule; e^t/2 should work e^(t/2) x' +e^(t/2) x/2 = e^(t/2)3t^2/2 when we integrate both sides we get \[e^{t/2}x= \int e^{t/2}\frac{3t^2}{2}dt\]
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
trial soln. is at^2 + bt +c 2x' = 4at + 2b x= at^2 +bt +c a=3 4a+b =0 2b+c =0 b=12 c=24
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
\[\int e^{t/2}\frac{3t^2}{2}dt\] e^(t/2) +t^2 2e^(t/2) 2t 4e^(t/2) +2 8e^(t/2) \[2*\frac32e^{t/2}(t^24t+8)\]
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
forgot the +C at the end:) this gives us \[e^{t/2}x=3e^{t/2}(t^24t+8)+C\] divide off the e^{t/2} \[x=3(t^24t+8)+Ce^{t/2}\]
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
my idea was undetermined coeffs tho was it
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
*wasnt .... ugh, when things slow down, they sloowww down
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
I did it the 'integrating factor' way too, just because I was curious... fair bit of work doing that integral..
 2 years ago
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