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anonymous
 4 years ago
In figure below if a charge of 4uc flows from the 6V battery to plate P of the 1 uF capacitor. what charge flow from
a  Q to R
b  S to the battery
c  What is the pd across C1 and C2
d  What is capacitance of C2
e  What is the single capacitor which is equivalent to C1 and C2 in series and what charge would it store?
anonymous
 4 years ago
In figure below if a charge of 4uc flows from the 6V battery to plate P of the 1 uF capacitor. what charge flow from a  Q to R b  S to the battery c  What is the pd across C1 and C2 d  What is capacitance of C2 e  What is the single capacitor which is equivalent to C1 and C2 in series and what charge would it store?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1349123247879:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0a. 4uC b. 4uC c. 6V d. \[Q = C _{eq}V\] \[\frac{ 1 }{ C _{eq}} = \frac{ 1 }{ C _{1}}+\frac{ 1 }{ C _{2}}\] \[Q = ( \frac{ 1 }{ C _{1}}+\frac{ 1 }{ C _{2}})^{1}V\]

masumanwar
 4 years ago
Best ResponseYou've already chosen the best response.0use conservation of charge

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Algebraic! please can you explain how u derived a,b,c

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if +4uC is on the plate at P then 4uC will be on the plate at Q meaning +4uC flowed to the plate at R meaning that there's  4 uC at the plate at S meaning +4uC flowed to the terminal of the battery. For c. ) I did the total voltage drop, which must be 6V, you could also do the drop per capacitor, and then find the capacitance of c2 from that. I didn't do it that way, I combined the solution to d and e into one part instead.
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