A community for students.
Here's the question you clicked on:
 0 viewing

This Question is Closed

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0for #10 try \((x3)(x+2)=0\) and solve for \(x\)

AdhaZeera
 2 years ago
Best ResponseYou've already chosen the best response.0It's on the sheet but here: 10. ? 11. 4 times 12. f(x)=f(x) 13. ? 14. End Behavior = neg. infinity, neg. infinity 15. (on sheet) 16. x=3 cubic; x=3 quadratic; x=2 linear

AdhaZeera
 2 years ago
Best ResponseYou've already chosen the best response.0@satellite73 So 10 is x=3 and x=2, right?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1when u put M(x) =0, how many values of x do u get ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1then it will cut xaxis 2 times .

AdhaZeera
 2 years ago
Best ResponseYou've already chosen the best response.0Ok, thanks. Is everything else correct?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1rest all seems fine....u need help with 10 and 13 ?

AdhaZeera
 2 years ago
Best ResponseYou've already chosen the best response.0I got 10, just 13 now

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1\(\text{ Equation of degree n>n zeros }\)

AdhaZeera
 2 years ago
Best ResponseYou've already chosen the best response.0I'm still confused :3

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1if there are n zeros, then the degree of eqution must be n

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1the lowest possible degree is asked, which will be 2
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.