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AdhaZeera

  • 3 years ago

Check my answers and help on #10 & #13

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  1. AdhaZeera
    • 3 years ago
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  2. hartnn
    • 3 years ago
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    what answers u got ?

  3. anonymous
    • 3 years ago
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    for #10 try \((x-3)(x+2)=0\) and solve for \(x\)

  4. AdhaZeera
    • 3 years ago
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    It's on the sheet but here: 10. ? 11. 4 times 12. f(-x)=f(x) 13. ? 14. End Behavior = neg. infinity, neg. infinity 15. (on sheet) 16. x=3 cubic; x=-3 quadratic; x=2 linear

  5. hartnn
    • 3 years ago
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    11. seems incorrect

  6. AdhaZeera
    • 3 years ago
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    @satellite73 So 10 is x=3 and x=-2, right?

  7. AdhaZeera
    • 3 years ago
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    @hartnn 3?

  8. hartnn
    • 3 years ago
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    when u put M(x) =0, how many values of x do u get ?

  9. AdhaZeera
    • 3 years ago
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    2

  10. hartnn
    • 3 years ago
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    then it will cut x-axis 2 times .

  11. AdhaZeera
    • 3 years ago
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    Ok, thanks. Is everything else correct?

  12. hartnn
    • 3 years ago
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    rest all seems fine....u need help with 10 and 13 ?

  13. AdhaZeera
    • 3 years ago
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    I got 10, just 13 now

  14. hartnn
    • 3 years ago
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    \(\text{ Equation of degree n---->n zeros }\)

  15. AdhaZeera
    • 3 years ago
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    I'm still confused :3

  16. hartnn
    • 3 years ago
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    if there are n zeros, then the degree of eqution must be n

  17. AdhaZeera
    • 3 years ago
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    \[x ^{2}?\]

  18. hartnn
    • 3 years ago
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    the lowest possible degree is asked, which will be 2

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