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anonymous
 4 years ago
How many milligrams of C atoms are in 2.04 x 10^20 molecules of ethanol?
anonymous
 4 years ago
How many milligrams of C atoms are in 2.04 x 10^20 molecules of ethanol?

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zepp
 4 years ago
Best ResponseYou've already chosen the best response.2Ethanol: \(\large \text{C}_2\text{H}_6\text{O}\)

zepp
 4 years ago
Best ResponseYou've already chosen the best response.2So first question, how many moles does 2.04 x 10^20 molecules represent?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why did u give Carbon2?

zepp
 4 years ago
Best ResponseYou've already chosen the best response.2Because that's the formula for Ethanol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[(6.02 \times 10^{23})(2.04 \times 10^{20})?\]

zepp
 4 years ago
Best ResponseYou've already chosen the best response.2That's incorrect; \[\large 1 \text{ mole}= 6.02×10^{23}\]

zepp
 4 years ago
Best ResponseYou've already chosen the best response.2\[\large ? \text{ mole}=2.04×10^{20}\]

zepp
 4 years ago
Best ResponseYou've already chosen the best response.2That's a proportion and you should have this: \(\LARGE \frac{2.04×10^{20}}{6.02×10^{23}}\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh so its divide instead of multiply?

zepp
 4 years ago
Best ResponseYou've already chosen the best response.2Yes, that's algebraic manipulation.

zepp
 4 years ago
Best ResponseYou've already chosen the best response.2Once you get that, you'll get the number of moles this quantity of molecules represent, are afterward, you may convert that easily to its mass through the molar mass.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1349138080842:dw

zepp
 4 years ago
Best ResponseYou've already chosen the best response.2\[\large \frac{1 \text{ mole}}{6.02*10^{23} \text{ atoms}}=\frac{x \text{ mole}}{2.04 * 10^{20}\text{ atoms}}\]Multiply both sides by 2.04*10^20\[\large \frac{2.04*10^{20}\text{ atoms}*1 \text{ mole}}{6.02*10^{23} \text{ atoms}}=x \text{ mole}\]

zepp
 4 years ago
Best ResponseYou've already chosen the best response.2atoms and atoms simplify out, leaving the mole on both sides.\[\large \frac{2.04*10^{20}}{6.02*10^{23}}\text{mole}=x \text{ mole}\]

zepp
 4 years ago
Best ResponseYou've already chosen the best response.2You'll get as answer: \(\large x\text{ moles}\) Now you may proceed to transform this using \(\LARGE n=\frac{m}{M}\), where \(\large \text{n}\) is the number of moles, \(\large \text{m}\) is the mass in \(\large \textbf{grams}\) (so you'll need to retransform it into milligrams as you're asked to do) and \(\large \text{M}\) is the molar mass.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well for ethanol it self right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0would i multiply that by .0003

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so i got .0140 because i used 46.68*.0003

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats just grams right?

zepp
 4 years ago
Best ResponseYou've already chosen the best response.2Good, now you'll need to set up another proportion:\[ \frac{\text{Mass of Carbon in 1 mole of Ethanol}}{\text{Molar mass of Ethanol}}=\frac{\text{Mass of Carbon (Unknown) }}{\text{Mass of the Ethanol given to you}}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(?/46.68)=(?/.0140x10^3?)

zepp
 4 years ago
Best ResponseYou've already chosen the best response.2Mass of carbon in 1 mole of ethanol is a known number, 2*Molar mass of carbon, 12, 2*12 = 24.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh ok i see where you got that from

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(24/46.68) = (?/.0140x10^3?)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0was i correct on the second half too?

zepp
 4 years ago
Best ResponseYou've already chosen the best response.2I don't know, I didn't push the values in my calculator, I've shown you how to do these kind of problem, all the other mathematical manipulations/calculations should be done by you; the right method is shown so you can take down any question that looks like this.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I was asking about for the mass of the ethanol that the answer i found before right?

zepp
 4 years ago
Best ResponseYou've already chosen the best response.2Like I said, I don't know :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok so now i simple mult across top and bottom and cancel out to get my answer
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