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Ethanol: \(\large \text{C}_2\text{H}_6\text{O}\)

So first question, how many moles does 2.04 x 10^20 molecules represent?

its not CH(Sub 6)O?

why did u give Carbon2?

Because that's the formula for Ethanol

It's a 2-carbon alcohol.

\[(6.02 \times 10^{23})(2.04 \times 10^{20})?\]

oh ok

That's incorrect;
\[\large 1 \text{ mole}= 6.02×10^{23}\]

\[\large ? \text{ mole}=2.04×10^{20}\]

That's a proportion and you should have this: \(\LARGE \frac{2.04×10^{20}}{6.02×10^{23}}\)

oh so its divide instead of multiply?

Yes, that's algebraic manipulation.

|dw:1349138080842:dw|

Why 1000?

for milligrams?

Our units are in moles...

ok i see

i got .0003 correct?

Molar mass is 46.07?

Yes

well for ethanol it self right?

would i multiply that by .0003

Exact.

46.68->46.7 sorry

so i got .0140 because i used 46.68*.0003

thats just grams right?

Yep

.0140 x 10^-3 ?

(?/46.68)=(?/.0140x10^-3?)

Mass of carbon in 1 mole of ethanol is a known number, 2*Molar mass of carbon, 12, 2*12 = 24.

oh ok i see where you got that from

(24/46.68) = (?/.0140x10^-3?)

was i correct on the second half too?

I was asking about for the mass of the ethanol that the answer i found before right?

Like I said, I don't know :)

Ok so now i simple mult across top and bottom and cancel out to get my answer

simply*

i think i have it

thank you

np