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shaqadry

how to differentiate f(x) = ln ( 1 + √ x / 1 - √ x )

  • one year ago
  • one year ago

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  1. Jemurray3
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    In general, \[ \frac{d}{dx} \ln( f(x) ) = \frac{1}{f(x)}\cdot f'(x)\]

    • one year ago
  2. shaqadry
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    how do i solve it? i cant seem to get the correct answer.

    • one year ago
  3. Ahaanomegas
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    Hint: You will have to use the chain rule by finding the derivative of the argument and multiplying it by the derivative that results without the chain rule. Are you aware of how to use the Chain Rule? If not, then I'll provide a solution.

    • one year ago
  4. shaqadry
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    im aware of it. but how do i calculate it?

    • one year ago
  5. Ahaanomegas
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    The derivative of the argument, you mean?

    • one year ago
  6. shaqadry
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    how do i apply chain rule in this equation

    • one year ago
  7. ByteMe
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    Rewrite f(x): \(\Large f(x)=ln\frac{1+\sqrt x}{1-\sqrt x}=ln(1+\sqrt x)-ln(1-\sqrt x) \) now just take the derivatives of each ln separately....

    • one year ago
  8. Ahaanomegas
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    Would you mind showing us your work? What have you found for the derivative of the argument of the natural log?

    • one year ago
  9. shaqadry
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    dy/dx = [ (1/1+√ x) (+ 1/2√x) ] - [ (1/1-√x) - ( 1/2√ x) ]

    • one year ago
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