anonymous
  • anonymous
how to differentiate f(x) = ln ( 1 + √ x / 1 - √ x )
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
In general, \[ \frac{d}{dx} \ln( f(x) ) = \frac{1}{f(x)}\cdot f'(x)\]
anonymous
  • anonymous
how do i solve it? i cant seem to get the correct answer.
anonymous
  • anonymous
Hint: You will have to use the chain rule by finding the derivative of the argument and multiplying it by the derivative that results without the chain rule. Are you aware of how to use the Chain Rule? If not, then I'll provide a solution.

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anonymous
  • anonymous
im aware of it. but how do i calculate it?
anonymous
  • anonymous
The derivative of the argument, you mean?
anonymous
  • anonymous
how do i apply chain rule in this equation
anonymous
  • anonymous
Rewrite f(x): \(\Large f(x)=ln\frac{1+\sqrt x}{1-\sqrt x}=ln(1+\sqrt x)-ln(1-\sqrt x) \) now just take the derivatives of each ln separately....
anonymous
  • anonymous
Would you mind showing us your work? What have you found for the derivative of the argument of the natural log?
anonymous
  • anonymous
dy/dx = [ (1/1+√ x) (+ 1/2√x) ] - [ (1/1-√x) - ( 1/2√ x) ]

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