## shaqadry 2 years ago how to differentiate f(x) = ln ( 1 + √ x / 1 - √ x )

1. Jemurray3

In general, $\frac{d}{dx} \ln( f(x) ) = \frac{1}{f(x)}\cdot f'(x)$

how do i solve it? i cant seem to get the correct answer.

3. Ahaanomegas

Hint: You will have to use the chain rule by finding the derivative of the argument and multiplying it by the derivative that results without the chain rule. Are you aware of how to use the Chain Rule? If not, then I'll provide a solution.

im aware of it. but how do i calculate it?

5. Ahaanomegas

The derivative of the argument, you mean?

how do i apply chain rule in this equation

7. ByteMe

Rewrite f(x): $$\Large f(x)=ln\frac{1+\sqrt x}{1-\sqrt x}=ln(1+\sqrt x)-ln(1-\sqrt x)$$ now just take the derivatives of each ln separately....

8. Ahaanomegas

Would you mind showing us your work? What have you found for the derivative of the argument of the natural log?