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Jemurray3Best ResponseYou've already chosen the best response.0
In general, \[ \frac{d}{dx} \ln( f(x) ) = \frac{1}{f(x)}\cdot f'(x)\]
 one year ago

shaqadryBest ResponseYou've already chosen the best response.0
how do i solve it? i cant seem to get the correct answer.
 one year ago

AhaanomegasBest ResponseYou've already chosen the best response.0
Hint: You will have to use the chain rule by finding the derivative of the argument and multiplying it by the derivative that results without the chain rule. Are you aware of how to use the Chain Rule? If not, then I'll provide a solution.
 one year ago

shaqadryBest ResponseYou've already chosen the best response.0
im aware of it. but how do i calculate it?
 one year ago

AhaanomegasBest ResponseYou've already chosen the best response.0
The derivative of the argument, you mean?
 one year ago

shaqadryBest ResponseYou've already chosen the best response.0
how do i apply chain rule in this equation
 one year ago

ByteMeBest ResponseYou've already chosen the best response.1
Rewrite f(x): \(\Large f(x)=ln\frac{1+\sqrt x}{1\sqrt x}=ln(1+\sqrt x)ln(1\sqrt x) \) now just take the derivatives of each ln separately....
 one year ago

AhaanomegasBest ResponseYou've already chosen the best response.0
Would you mind showing us your work? What have you found for the derivative of the argument of the natural log?
 one year ago

shaqadryBest ResponseYou've already chosen the best response.0
dy/dx = [ (1/1+√ x) (+ 1/2√x) ]  [ (1/1√x)  ( 1/2√ x) ]
 one year ago
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