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shaqadry
 3 years ago
how to differentiate f(x) = ln ( 1 + √ x / 1  √ x )
shaqadry
 3 years ago
how to differentiate f(x) = ln ( 1 + √ x / 1  √ x )

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Jemurray3
 3 years ago
Best ResponseYou've already chosen the best response.0In general, \[ \frac{d}{dx} \ln( f(x) ) = \frac{1}{f(x)}\cdot f'(x)\]

shaqadry
 3 years ago
Best ResponseYou've already chosen the best response.0how do i solve it? i cant seem to get the correct answer.

Ahaanomegas
 3 years ago
Best ResponseYou've already chosen the best response.0Hint: You will have to use the chain rule by finding the derivative of the argument and multiplying it by the derivative that results without the chain rule. Are you aware of how to use the Chain Rule? If not, then I'll provide a solution.

shaqadry
 3 years ago
Best ResponseYou've already chosen the best response.0im aware of it. but how do i calculate it?

Ahaanomegas
 3 years ago
Best ResponseYou've already chosen the best response.0The derivative of the argument, you mean?

shaqadry
 3 years ago
Best ResponseYou've already chosen the best response.0how do i apply chain rule in this equation

ByteMe
 3 years ago
Best ResponseYou've already chosen the best response.1Rewrite f(x): \(\Large f(x)=ln\frac{1+\sqrt x}{1\sqrt x}=ln(1+\sqrt x)ln(1\sqrt x) \) now just take the derivatives of each ln separately....

Ahaanomegas
 3 years ago
Best ResponseYou've already chosen the best response.0Would you mind showing us your work? What have you found for the derivative of the argument of the natural log?

shaqadry
 3 years ago
Best ResponseYou've already chosen the best response.0dy/dx = [ (1/1+√ x) (+ 1/2√x) ]  [ (1/1√x)  ( 1/2√ x) ]
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