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Jemurray3 Group TitleBest ResponseYou've already chosen the best response.0
In general, \[ \frac{d}{dx} \ln( f(x) ) = \frac{1}{f(x)}\cdot f'(x)\]
 2 years ago

shaqadry Group TitleBest ResponseYou've already chosen the best response.0
how do i solve it? i cant seem to get the correct answer.
 2 years ago

Ahaanomegas Group TitleBest ResponseYou've already chosen the best response.0
Hint: You will have to use the chain rule by finding the derivative of the argument and multiplying it by the derivative that results without the chain rule. Are you aware of how to use the Chain Rule? If not, then I'll provide a solution.
 2 years ago

shaqadry Group TitleBest ResponseYou've already chosen the best response.0
im aware of it. but how do i calculate it?
 2 years ago

Ahaanomegas Group TitleBest ResponseYou've already chosen the best response.0
The derivative of the argument, you mean?
 2 years ago

shaqadry Group TitleBest ResponseYou've already chosen the best response.0
how do i apply chain rule in this equation
 2 years ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
Rewrite f(x): \(\Large f(x)=ln\frac{1+\sqrt x}{1\sqrt x}=ln(1+\sqrt x)ln(1\sqrt x) \) now just take the derivatives of each ln separately....
 2 years ago

Ahaanomegas Group TitleBest ResponseYou've already chosen the best response.0
Would you mind showing us your work? What have you found for the derivative of the argument of the natural log?
 2 years ago

shaqadry Group TitleBest ResponseYou've already chosen the best response.0
dy/dx = [ (1/1+√ x) (+ 1/2√x) ]  [ (1/1√x)  ( 1/2√ x) ]
 2 years ago
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