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monroe17

  • 2 years ago

Suppose that f(x)=((5x)/((2-2x)^5) Find an equation for the tangent line to the graph of at x=2.

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  1. monroe17
    • 2 years ago
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    y= -5/16 x= 2 y'=((5(4x+1))/((32(x-1)^6))) y'(2)=45/32 45/32=slope (y-(-5/16))=45/32(x-2) (y+5/16)=45/32(x-2) (y+5/16)=45/32x-19/32 y=45/32x-29/32 this is what I came up with and it's wrong... Can someone help me?

  2. eyust707
    • 2 years ago
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    This step is incorrect: (y+5/16)=45/32(x-2) (y+5/16)=45/32x-19/32 |dw:1349146268366:dw|

  3. eyust707
    • 2 years ago
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    |dw:1349146299595:dw|

  4. eyust707
    • 2 years ago
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    |dw:1349146340167:dw|

  5. monroe17
    • 2 years ago
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    45/32x-19/32... that's what i keep getting

  6. eyust707
    • 2 years ago
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    |dw:1349146416842:dw|

  7. eyust707
    • 2 years ago
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    |dw:1349146449142:dw|

  8. monroe17
    • 2 years ago
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    haha ohh.. stupid me

  9. eyust707
    • 2 years ago
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    =) great job otherwise!!! you did all the hard stuff perfectly! +fan

  10. monroe17
    • 2 years ago
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    yay! thank you!

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