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zurf

Find the derivative of f(x) = -cos (2x^2-3)

  • one year ago
  • one year ago

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  1. wio
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    Do you know how to use the chain rule?

    • one year ago
  2. zurf
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    yeah yes i do

    • one year ago
  3. wio
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    Well your inner function is \(2x^2-3\) and your outer function is \(-\cos(x)\). There shouldn't be anything hard about this.

    • one year ago
  4. zurf
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    do we have to use chain rule ? i'm confused on what we should do when with the -cos

    • one year ago
  5. wio
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    The - is just \(-1\cdot \cos(x)\). It's a constant. You can pull it out and put it back in after.

    • one year ago
  6. zurf
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    oh really? but this have to use f(x+h)-f(x) first derivation ..

    • one year ago
  7. wio
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    You have to use this you mean? \[\Large \lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}\]

    • one year ago
  8. wio
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    You're not allowed to use the chain rule?

    • one year ago
  9. zurf
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    Oh sorry, i just realised it only has to use chain rule. I make things go more complicated -_-

    • one year ago
  10. wio
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    So can you do it now?

    • one year ago
  11. zurf
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    yeah the answer is sin(2x^2-3)(4x) right ?

    • one year ago
  12. RadEn
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    yeah, i agree that

    • one year ago
  13. zurf
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    Oh thank you so much :D

    • one year ago
  14. wio
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    It's correct.

    • one year ago
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