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Find the derivative of f(x) = -cos (2x^2-3)

Mathematics
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Do you know how to use the chain rule?
yeah yes i do
Well your inner function is \(2x^2-3\) and your outer function is \(-\cos(x)\). There shouldn't be anything hard about this.

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Other answers:

do we have to use chain rule ? i'm confused on what we should do when with the -cos
The - is just \(-1\cdot \cos(x)\). It's a constant. You can pull it out and put it back in after.
oh really? but this have to use f(x+h)-f(x) first derivation ..
You have to use this you mean? \[\Large \lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}\]
You're not allowed to use the chain rule?
Oh sorry, i just realised it only has to use chain rule. I make things go more complicated -_-
So can you do it now?
yeah the answer is sin(2x^2-3)(4x) right ?
yeah, i agree that
Oh thank you so much :D
It's correct.

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