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the x^2 + 2x + 1 is thw square of (x + 1)^2
as per the previous questions you can solve it

The first part would be (x -2) 2x? + 1

Yes!

@theredhead1617 do you know how to solve the problem

No @miteshchvm I dont understand how to. I wish to know where to begin but i do not

can you factorise x^2 + 2x + 1?

x^2 + 2x + 1 = (x + 1)^2 = (x+1)(x+1)
x^2 - 1 = (x +1)(x - 1)
x^2 - 4 = (x-2)(x+2)
you get it?

(x + 1) to second power?

yes

just a little bit, its hard

now refer to my first comment

on the previous question?

you get it?

im getting a better understand of it

A:

B:

C:

D:

on eliminating values you get
\[\frac{ (x+1)(x+2) }{ (x-1) }\]

thanks for everything @miteshchvm