Let h(x)=f(x)⋅g(x), and k(x)=f(x)/g(x). Use the figures below to find the values of the indicated derivatives.
http://www.flickr.com/photos/57417292@N03/6212910338/in/photostream http://www.flickr.com/photos/57417292@N03/6212910354/in/photostream
These two are the graphs

- anonymous

- chestercat

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- anonymous

I tried everything but could seem to find the right answer

- anonymous

Did you try google?

- anonymous

yeah I couldnt find help there either, have no clue

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## More answers

- anonymous

Remember that the derivative is the slope of a line.

- anonymous

Hmmm

- anonymous

yes I've tried that too and I believe the slope of the line is equal to the slope of the tangent line too

- anonymous

and the slope of the tangent line equals the derivative

- anonymous

however I keep getting the wrong answer

- anonymous

That's so weird O.o

- anonymous

What answers are you getting?

- anonymous

Do they want you to get the derivative at certain points or what?

- anonymous

I got 2/3 for prime
but whats the te value of g(1)

- anonymous

they want k(1)

- anonymous

They want g(1) and k(1)? They don't want the derivative?

- anonymous

they want k(1) and k is equal to f(x)/g(x)
I got slope 2/3
for f(x)

- anonymous

and F'(1) is zero
because thats where u have an x intercept

- anonymous

and the equation simplifies to f(x)g(x)

- anonymous

over g(x)^2

- anonymous

Okay, so what are the graphs you posted?

- anonymous

those are the functions of f(x) and g(x)
they are the functions

- anonymous

So since f(1) = 1 and g(1) = 1.25, k(1) = 1 / 1.25

- anonymous

f'(1) = 2/3 since it rises 2 and runs 3 when x is 1

- anonymous

I don't see what's hard about this

- anonymous

How is g(1) = 1.25 when its not given

- anonymous

Well, from the left side you can see the slope is -2, so it has to hit at the half way point

- anonymous

Then it goes through the origin

- anonymous

So it is rising 2/1.5

- anonymous

4/3

- anonymous

thank you sooo much!! god blesss u !!! may u live happily ever after!!

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