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just differentiate the cubic equation to get f'(x)

now f'(3) will give you slope of tangent

24x^2-18x

f'(3)?

yep substite x=3 in the differential

so slope is 162

so now the mx+b?

slope point form
y-y1=m(x-x1)

gt it?

yeah

:)

y-140=162(x-3)?

right

yep

thanks

welcomes