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Ldaniel Group Title

Find the equation of the line tangent to the graph of f at (3, 140), where f is given by f(x) = 8x^3 − 9x^2 + 5.

  • one year ago
  • one year ago

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  1. AravindG Group Title
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    just differentiate the cubic equation to get f'(x)

    • one year ago
  2. AravindG Group Title
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    now f'(3) will give you slope of tangent

    • one year ago
  3. Ldaniel Group Title
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    24x^2-18x

    • one year ago
  4. AravindG Group Title
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    now you have slope of tangent and a point in the tangent , use slope point form to write equation of tangent

    • one year ago
  5. Ldaniel Group Title
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    f'(3)?

    • one year ago
  6. AravindG Group Title
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    yep substite x=3 in the differential

    • one year ago
  7. Ldaniel Group Title
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    so slope is 162

    • one year ago
  8. Ldaniel Group Title
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    so now the mx+b?

    • one year ago
  9. AravindG Group Title
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    slope point form y-y1=m(x-x1)

    • one year ago
  10. AravindG Group Title
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    gt it?

    • one year ago
  11. Ldaniel Group Title
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    yeah

    • one year ago
  12. AravindG Group Title
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    :)

    • one year ago
  13. Ldaniel Group Title
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    y-140=162(x-3)?

    • one year ago
  14. Ldaniel Group Title
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    right

    • one year ago
  15. AravindG Group Title
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    yep

    • one year ago
  16. Ldaniel Group Title
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    thanks

    • one year ago
  17. AravindG Group Title
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    welcomes

    • one year ago
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