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anonymous
 3 years ago
Find the equation of the line tangent to the graph of f at (3, 140), where f is given by f(x) = 8x^3 − 9x^2 + 5.
anonymous
 3 years ago
Find the equation of the line tangent to the graph of f at (3, 140), where f is given by f(x) = 8x^3 − 9x^2 + 5.

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AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1just differentiate the cubic equation to get f'(x)

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1now f'(3) will give you slope of tangent

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1now you have slope of tangent and a point in the tangent , use slope point form to write equation of tangent

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1yep substite x=3 in the differential

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1slope point form yy1=m(xx1)
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