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Ldaniel

  • 3 years ago

Find the equation of the line tangent to the graph of f at (3, 140), where f is given by f(x) = 8x^3 − 9x^2 + 5.

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  1. AravindG
    • 3 years ago
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    just differentiate the cubic equation to get f'(x)

  2. AravindG
    • 3 years ago
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    now f'(3) will give you slope of tangent

  3. Ldaniel
    • 3 years ago
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    24x^2-18x

  4. AravindG
    • 3 years ago
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    now you have slope of tangent and a point in the tangent , use slope point form to write equation of tangent

  5. Ldaniel
    • 3 years ago
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    f'(3)?

  6. AravindG
    • 3 years ago
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    yep substite x=3 in the differential

  7. Ldaniel
    • 3 years ago
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    so slope is 162

  8. Ldaniel
    • 3 years ago
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    so now the mx+b?

  9. AravindG
    • 3 years ago
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    slope point form y-y1=m(x-x1)

  10. AravindG
    • 3 years ago
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    gt it?

  11. Ldaniel
    • 3 years ago
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    yeah

  12. AravindG
    • 3 years ago
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    :)

  13. Ldaniel
    • 3 years ago
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    y-140=162(x-3)?

  14. Ldaniel
    • 3 years ago
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    right

  15. AravindG
    • 3 years ago
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    yep

  16. Ldaniel
    • 3 years ago
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    thanks

  17. AravindG
    • 3 years ago
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    welcomes

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