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Ldaniel
Group Title
Find the equation of the line tangent to the graph of f at (3, 140), where f is given by f(x) = 8x^3 − 9x^2 + 5.
 2 years ago
 2 years ago
Ldaniel Group Title
Find the equation of the line tangent to the graph of f at (3, 140), where f is given by f(x) = 8x^3 − 9x^2 + 5.
 2 years ago
 2 years ago

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AravindG Group TitleBest ResponseYou've already chosen the best response.1
just differentiate the cubic equation to get f'(x)
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
now f'(3) will give you slope of tangent
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
now you have slope of tangent and a point in the tangent , use slope point form to write equation of tangent
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
yep substite x=3 in the differential
 2 years ago

Ldaniel Group TitleBest ResponseYou've already chosen the best response.0
so slope is 162
 2 years ago

Ldaniel Group TitleBest ResponseYou've already chosen the best response.0
so now the mx+b?
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
slope point form yy1=m(xx1)
 2 years ago

Ldaniel Group TitleBest ResponseYou've already chosen the best response.0
y140=162(x3)?
 2 years ago
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