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98x + 133y = 427
Specify particular the answers (x,y) where x>0 and y>0
I get the answer (244,183) or the general answer x= 19n244 y= 18314n
I don't really get the x>0, y>0 part, could anyone guide me through it?
 one year ago
 one year ago
98x + 133y = 427 Specify particular the answers (x,y) where x>0 and y>0 I get the answer (244,183) or the general answer x= 19n244 y= 18314n I don't really get the x>0, y>0 part, could anyone guide me through it?
 one year ago
 one year ago

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mukushlaBest ResponseYou've already chosen the best response.1
they want u to find n's for which x and y are positive so u need to solve this inequalities \[19n244>0\]\[18314n>0\]
 one year ago

frxBest ResponseYou've already chosen the best response.0
So the answer should just be where \[n >\frac{ 244 }{ 19 }\] or \[n <\frac{ 183 }{ 14 }\] Right?
 one year ago

mukushlaBest ResponseYou've already chosen the best response.1
not or ... it is and...
 one year ago

mukushlaBest ResponseYou've already chosen the best response.1
thats right ...just note that they are simultaneous
 one year ago

frxBest ResponseYou've already chosen the best response.0
So the answer lies within the interval \[\frac{ 244 }{ 19}< n < \frac{ 183 }{14}\] ?
 one year ago

mukushlaBest ResponseYou've already chosen the best response.1
just one number satisfies that inequalities :)
 one year ago

frxBest ResponseYou've already chosen the best response.0
13, thanks alot for your help! :D
 one year ago
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