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frx

  • 2 years ago

98x + 133y = 427 Specify particular the answers (x,y) where x>0 and y>0 I get the answer (-244,183) or the general answer x= 19n-244 y= 183-14n I don't really get the x>0, y>0 part, could anyone guide me through it?

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  1. mukushla
    • 2 years ago
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    they want u to find n's for which x and y are positive so u need to solve this inequalities \[19n-244>0\]\[183-14n>0\]

  2. frx
    • 2 years ago
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    So the answer should just be where \[n >\frac{ 244 }{ 19 }\] or \[n <\frac{ 183 }{ 14 }\] Right?

  3. mukushla
    • 2 years ago
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    not or ... it is and...

  4. mukushla
    • 2 years ago
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    thats right ...just note that they are simultaneous

  5. frx
    • 2 years ago
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    So the answer lies within the interval \[\frac{ 244 }{ 19}< n < \frac{ 183 }{14}\] ?

  6. mukushla
    • 2 years ago
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    exactly

  7. mukushla
    • 2 years ago
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    just one number satisfies that inequalities :)

  8. frx
    • 2 years ago
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    13, thanks alot for your help! :D

  9. mukushla
    • 2 years ago
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    no problem

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