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anonymous
 4 years ago
98x + 133y = 427
Specify particular the answers (x,y) where x>0 and y>0
I get the answer (244,183) or the general answer x= 19n244 y= 18314n
I don't really get the x>0, y>0 part, could anyone guide me through it?
anonymous
 4 years ago
98x + 133y = 427 Specify particular the answers (x,y) where x>0 and y>0 I get the answer (244,183) or the general answer x= 19n244 y= 18314n I don't really get the x>0, y>0 part, could anyone guide me through it?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0they want u to find n's for which x and y are positive so u need to solve this inequalities \[19n244>0\]\[18314n>0\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So the answer should just be where \[n >\frac{ 244 }{ 19 }\] or \[n <\frac{ 183 }{ 14 }\] Right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0not or ... it is and...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats right ...just note that they are simultaneous

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So the answer lies within the interval \[\frac{ 244 }{ 19}< n < \frac{ 183 }{14}\] ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just one number satisfies that inequalities :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.013, thanks alot for your help! :D
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