Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

frx

  • 3 years ago

98x + 133y = 427 Specify particular the answers (x,y) where x>0 and y>0 I get the answer (-244,183) or the general answer x= 19n-244 y= 183-14n I don't really get the x>0, y>0 part, could anyone guide me through it?

  • This Question is Closed
  1. mukushla
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    they want u to find n's for which x and y are positive so u need to solve this inequalities \[19n-244>0\]\[183-14n>0\]

  2. frx
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So the answer should just be where \[n >\frac{ 244 }{ 19 }\] or \[n <\frac{ 183 }{ 14 }\] Right?

  3. mukushla
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    not or ... it is and...

  4. mukushla
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    thats right ...just note that they are simultaneous

  5. frx
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So the answer lies within the interval \[\frac{ 244 }{ 19}< n < \frac{ 183 }{14}\] ?

  6. mukushla
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    exactly

  7. mukushla
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    just one number satisfies that inequalities :)

  8. frx
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    13, thanks alot for your help! :D

  9. mukushla
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    no problem

  10. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy