Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
frx
Group Title
98x + 133y = 427
Specify particular the answers (x,y) where x>0 and y>0
I get the answer (244,183) or the general answer x= 19n244 y= 18314n
I don't really get the x>0, y>0 part, could anyone guide me through it?
 one year ago
 one year ago
frx Group Title
98x + 133y = 427 Specify particular the answers (x,y) where x>0 and y>0 I get the answer (244,183) or the general answer x= 19n244 y= 18314n I don't really get the x>0, y>0 part, could anyone guide me through it?
 one year ago
 one year ago

This Question is Closed

mukushla Group TitleBest ResponseYou've already chosen the best response.1
they want u to find n's for which x and y are positive so u need to solve this inequalities \[19n244>0\]\[18314n>0\]
 one year ago

frx Group TitleBest ResponseYou've already chosen the best response.0
So the answer should just be where \[n >\frac{ 244 }{ 19 }\] or \[n <\frac{ 183 }{ 14 }\] Right?
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.1
not or ... it is and...
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.1
thats right ...just note that they are simultaneous
 one year ago

frx Group TitleBest ResponseYou've already chosen the best response.0
So the answer lies within the interval \[\frac{ 244 }{ 19}< n < \frac{ 183 }{14}\] ?
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.1
just one number satisfies that inequalities :)
 one year ago

frx Group TitleBest ResponseYou've already chosen the best response.0
13, thanks alot for your help! :D
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.1
no problem
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.