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# Let $f(x) = x^2 - 2x +1$ use the epsilon-delta definition to show that: $\lim_{x \rightarrow 3} f(x) = 4$ I've come up with this: $|( x-1)^2 - 4| < \epsilon$ $| x-3| < \sqrt{\epsilon }$ Set delta as the squareroot of epsilon: $| x-3| < \delta =\sqrt{\epsilon }$ How do I finish this, I get it all wrong by taking the left expresson to the second power

OCW Scholar - Single Variable Calculus