Let \[f(x) = x^2 - 2x +1 \] use the epsilon-delta definition to show that: \[\lim_{x \rightarrow 3} f(x) = 4\]
I've come up with this:
\[|( x-1)^2 - 4| < \epsilon \]
\[| x-3| < \sqrt{\epsilon } \]
Set delta as the squareroot of epsilon:
\[| x-3| < \delta =\sqrt{\epsilon } \]
How do I finish this, I get it all wrong by taking the left expresson to the second power

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Ok. I couldn't read that little number.

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