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baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.0A fish tank initially has 4kg of salt dissolved in 100L of water.

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.0It is decided that this concentration is too high! So, fresh water is mixed at a rate of 10L/mind, while 10L of mixture is removed per minute.

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.0If x kg/L is the concentration of the saltwater solution in the tank t seconds after the fresh water is first added, find the differential equation for x.

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.0I thought dx/dt = 10x

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.0But i got the answer wrong

suvesh253
 2 years ago
Best ResponseYou've already chosen the best response.0water remains constant at 100L. Only salt concentration changing with time

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.0So concentration = 100x?

suvesh253
 2 years ago
Best ResponseYou've already chosen the best response.0i think it will be dx/dt = 4  0.4t

suvesh253
 2 years ago
Best ResponseYou've already chosen the best response.0sorry 100 dx/dt = 4  0.4t

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.0I got the solution, it says 10dx/dt + x = 0

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.0But i dont know how they got that

suvesh253
 2 years ago
Best ResponseYou've already chosen the best response.0maybe it's like this : salt concentration is being reduced by 10 X / 100 L where x is salt concentration and water remains constant so only changing thing is 10 L of solution being removed
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