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baddinlolBest ResponseYou've already chosen the best response.0
A fish tank initially has 4kg of salt dissolved in 100L of water.
 one year ago

baddinlolBest ResponseYou've already chosen the best response.0
It is decided that this concentration is too high! So, fresh water is mixed at a rate of 10L/mind, while 10L of mixture is removed per minute.
 one year ago

baddinlolBest ResponseYou've already chosen the best response.0
If x kg/L is the concentration of the saltwater solution in the tank t seconds after the fresh water is first added, find the differential equation for x.
 one year ago

baddinlolBest ResponseYou've already chosen the best response.0
I thought dx/dt = 10x
 one year ago

baddinlolBest ResponseYou've already chosen the best response.0
But i got the answer wrong
 one year ago

suvesh253Best ResponseYou've already chosen the best response.0
water remains constant at 100L. Only salt concentration changing with time
 one year ago

baddinlolBest ResponseYou've already chosen the best response.0
So concentration = 100x?
 one year ago

suvesh253Best ResponseYou've already chosen the best response.0
i think it will be dx/dt = 4  0.4t
 one year ago

suvesh253Best ResponseYou've already chosen the best response.0
sorry 100 dx/dt = 4  0.4t
 one year ago

baddinlolBest ResponseYou've already chosen the best response.0
I got the solution, it says 10dx/dt + x = 0
 one year ago

baddinlolBest ResponseYou've already chosen the best response.0
But i dont know how they got that
 one year ago

suvesh253Best ResponseYou've already chosen the best response.0
maybe it's like this : salt concentration is being reduced by 10 X / 100 L where x is salt concentration and water remains constant so only changing thing is 10 L of solution being removed
 one year ago
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