isolape
  • isolape
ax + r = 7 for r
Mathematics
schrodinger
  • schrodinger
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mathslover
  • mathslover
\[\color{blue}{\text{Subtract ax both sides}}\]
mathslover
  • mathslover
\[\large{\color{blue}{ax+r}=\color{red}{7}}\] \[\large{\color{blue}{ax+r}-\color{red}{ax}=\color{red}{7-ax}}\]
mathslover
  • mathslover
Can you tell me what will you get @isolape ?

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isolape
  • isolape
uhm. i wish i could honestly. but i have no idea how to do any of this.
mathslover
  • mathslover
what is 3-3 ? @isolape
isolape
  • isolape
dosn't make any sense to me.
isolape
  • isolape
0
mathslover
  • mathslover
so what will be : ax - ax ?
isolape
  • isolape
0...?
mathslover
  • mathslover
yes, so we had : ax - r - ax .. can you simplify it now?
isolape
  • isolape
Wait so is that the new equation after we -ax on both sides? ax - r - ax
mathslover
  • mathslover
yes
mathslover
  • mathslover
ax-r-ax = 7 - ax
isolape
  • isolape
uhm, do you add ax on both sides now?
mathslover
  • mathslover
ax-ax-r=7-ax
mathslover
  • mathslover
Now, ax-ax = 0 ax-ax-r = 7-ax => 0 - r = 7-ax correct?
isolape
  • isolape
correct
mathslover
  • mathslover
so we get r = ax - 7
mathslover
  • mathslover
got it?
isolape
  • isolape
so thats the answer?
mathslover
  • mathslover
yes
isolape
  • isolape
alright, i guess i got it. Thanks!

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