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shubhamsrgBest ResponseYou've already chosen the best response.0
or in other words 1/2 * summation ( n(n+1)/n! ) from n=1 or 0 ,,to infinity..
 one year ago

mukushlaBest ResponseYou've already chosen the best response.2
\[e^x=\sum_{n=0}^{\infty} \frac{x^n}{n!}\]take derivative\[e^x=\sum_{n=1}^{\infty} \frac{nx^{n1}}{n!}\]multiply by x^2\[x^2e^x=\sum_{n=1}^{\infty} \frac{nx^{n+1}}{n!}\]and ...
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
another derivative and then put x=1 !! thanks a lot!!
 one year ago
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