a Ferris wheel that rotates five times each minute. It carries each car around a circle of diameter 18.0 m. What force (magnitude and direction) does the seat exert on a 53.0-kg child when the rider is halfway between top and bottom?

- anonymous

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- anonymous

This question would be more suited in physics section.

- anonymous

yeah but they hardly ever have physics people on here

- anonymous

Haha

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## More answers

- anonymous

|dw:1349189537433:dw|

- anonymous

yes he can be anywhere it doesn't matter..

- anonymous

it says in the question 5 times each minute

- anonymous

i dont know where to start on this one

- anonymous

"..when the rider is halfway between top and bottom?"
|dw:1349189927715:dw|

- anonymous

ok

- anonymous

The resultant is the vector sum of the child's weight (up) and the centripetal force (towards center)

- anonymous

ok

- anonymous

and thats for start

- anonymous

Can you convert that 5rpm into a linear speed, or at least an angular velocity in radians per second?

- anonymous

5/60?

- anonymous

nope

- anonymous

That will give you revolutions per second, but you need to convert revolutions to something useful like radians or meters.

- anonymous

can you do it?

- anonymous

Yes, it's a pretty easy operation, but I think you'll get more satisfaction if you try it yourself.

- anonymous

I already did try, i couldn't do it

- anonymous

Would it be 90m/s

- anonymous

no idea?

- anonymous

May be the answer would be,
5300N clockwise

- anonymous

Try posting this in the physics section.
Surely you would get an answer.

- anonymous

how did you get that

- anonymous

A mistake it would be 530N
Well,
the weight of the child is 53 kg
gravitational acceleration appro. 10m/s2
then
force= mass * acceleration
= 53kg* 10m/s2
= 530kg/s2
= 530N

- anonymous

i think thats wrong

- anonymous

5rpm means 5 times 2π radians per minute. Divide by 60 to get radians/second.
Multiply that by the radius of 9m to get linear speed.
centripetal acceleration (just like in the last problem you did) is v^2/r.

- anonymous

i need to get going in about 10 minutes can you show me the steps and what the answer is so i can have a better understanding @CliffSedge

- anonymous

i got 4.71 after i multiplied it by 9

- anonymous

Ok, that will be your linear speed. Square that and divide by the radius to get centripetal acceleration. Mass times acceleration will give you force.
Use mg to find the weight force.
The resultant is the vector sum of those two forces.
If you don't know how to find resultant vectors, then please go back to your book and study.

- anonymous

so 388.76? is this correct, i only have 1 attempt left?

- anonymous

?

- anonymous

You need magnitude and direction. What is the direction of the force vector?

- anonymous

How did you get 388.76? What are the units of that number?

- anonymous

Did you get 2.467 m/s^2 for the centripetal acceleration?

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