## ilikephysics2 3 years ago a Ferris wheel that rotates five times each minute. It carries each car around a circle of diameter 18.0 m. What force (magnitude and direction) does the seat exert on a 53.0-kg child when the rider is halfway between top and bottom?

1. Miyuru

This question would be more suited in physics section.

2. ilikephysics2

yeah but they hardly ever have physics people on here

Haha

4. Miyuru

|dw:1349189537433:dw|

5. ilikephysics2

yes he can be anywhere it doesn't matter..

6. ilikephysics2

it says in the question 5 times each minute

7. ilikephysics2

i dont know where to start on this one

8. CliffSedge

"..when the rider is halfway between top and bottom?" |dw:1349189927715:dw|

9. ilikephysics2

ok

10. CliffSedge

The resultant is the vector sum of the child's weight (up) and the centripetal force (towards center)

11. ilikephysics2

ok

12. ilikephysics2

and thats for start

13. CliffSedge

Can you convert that 5rpm into a linear speed, or at least an angular velocity in radians per second?

14. ilikephysics2

5/60?

15. Miyuru

nope

16. CliffSedge

That will give you revolutions per second, but you need to convert revolutions to something useful like radians or meters.

17. ilikephysics2

can you do it?

18. CliffSedge

Yes, it's a pretty easy operation, but I think you'll get more satisfaction if you try it yourself.

19. ilikephysics2

I already did try, i couldn't do it

20. Miyuru

Would it be 90m/s

21. ilikephysics2

no idea?

22. Miyuru

May be the answer would be, 5300N clockwise

23. Miyuru

Try posting this in the physics section. Surely you would get an answer.

24. ilikephysics2

how did you get that

25. Miyuru

A mistake it would be 530N Well, the weight of the child is 53 kg gravitational acceleration appro. 10m/s2 then force= mass * acceleration = 53kg* 10m/s2 = 530kg/s2 = 530N

26. ilikephysics2

i think thats wrong

27. CliffSedge

5rpm means 5 times 2π radians per minute. Divide by 60 to get radians/second. Multiply that by the radius of 9m to get linear speed. centripetal acceleration (just like in the last problem you did) is v^2/r.

28. ilikephysics2

i need to get going in about 10 minutes can you show me the steps and what the answer is so i can have a better understanding @CliffSedge

29. ilikephysics2

i got 4.71 after i multiplied it by 9

30. CliffSedge

Ok, that will be your linear speed. Square that and divide by the radius to get centripetal acceleration. Mass times acceleration will give you force. Use mg to find the weight force. The resultant is the vector sum of those two forces. If you don't know how to find resultant vectors, then please go back to your book and study.

31. ilikephysics2

so 388.76? is this correct, i only have 1 attempt left?

32. ilikephysics2

?

33. CliffSedge

You need magnitude and direction. What is the direction of the force vector?

34. CliffSedge

How did you get 388.76? What are the units of that number?

35. CliffSedge

Did you get 2.467 m/s^2 for the centripetal acceleration?

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