anonymous
  • anonymous
a Ferris wheel that rotates five times each minute. It carries each car around a circle of diameter 18.0 m. What force (magnitude and direction) does the seat exert on a 53.0-kg child when the rider is halfway between top and bottom?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
This question would be more suited in physics section.
anonymous
  • anonymous
yeah but they hardly ever have physics people on here
anonymous
  • anonymous
Haha

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More answers

anonymous
  • anonymous
|dw:1349189537433:dw|
anonymous
  • anonymous
yes he can be anywhere it doesn't matter..
anonymous
  • anonymous
it says in the question 5 times each minute
anonymous
  • anonymous
i dont know where to start on this one
anonymous
  • anonymous
"..when the rider is halfway between top and bottom?" |dw:1349189927715:dw|
anonymous
  • anonymous
ok
anonymous
  • anonymous
The resultant is the vector sum of the child's weight (up) and the centripetal force (towards center)
anonymous
  • anonymous
ok
anonymous
  • anonymous
and thats for start
anonymous
  • anonymous
Can you convert that 5rpm into a linear speed, or at least an angular velocity in radians per second?
anonymous
  • anonymous
5/60?
anonymous
  • anonymous
nope
anonymous
  • anonymous
That will give you revolutions per second, but you need to convert revolutions to something useful like radians or meters.
anonymous
  • anonymous
can you do it?
anonymous
  • anonymous
Yes, it's a pretty easy operation, but I think you'll get more satisfaction if you try it yourself.
anonymous
  • anonymous
I already did try, i couldn't do it
anonymous
  • anonymous
Would it be 90m/s
anonymous
  • anonymous
no idea?
anonymous
  • anonymous
May be the answer would be, 5300N clockwise
anonymous
  • anonymous
Try posting this in the physics section. Surely you would get an answer.
anonymous
  • anonymous
how did you get that
anonymous
  • anonymous
A mistake it would be 530N Well, the weight of the child is 53 kg gravitational acceleration appro. 10m/s2 then force= mass * acceleration = 53kg* 10m/s2 = 530kg/s2 = 530N
anonymous
  • anonymous
i think thats wrong
anonymous
  • anonymous
5rpm means 5 times 2π radians per minute. Divide by 60 to get radians/second. Multiply that by the radius of 9m to get linear speed. centripetal acceleration (just like in the last problem you did) is v^2/r.
anonymous
  • anonymous
i need to get going in about 10 minutes can you show me the steps and what the answer is so i can have a better understanding @CliffSedge
anonymous
  • anonymous
i got 4.71 after i multiplied it by 9
anonymous
  • anonymous
Ok, that will be your linear speed. Square that and divide by the radius to get centripetal acceleration. Mass times acceleration will give you force. Use mg to find the weight force. The resultant is the vector sum of those two forces. If you don't know how to find resultant vectors, then please go back to your book and study.
anonymous
  • anonymous
so 388.76? is this correct, i only have 1 attempt left?
anonymous
  • anonymous
?
anonymous
  • anonymous
You need magnitude and direction. What is the direction of the force vector?
anonymous
  • anonymous
How did you get 388.76? What are the units of that number?
anonymous
  • anonymous
Did you get 2.467 m/s^2 for the centripetal acceleration?

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