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jkev1

  • 2 years ago

Find the number of real solutions for the equation 3x^2_6x+3=0

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  1. Coolsector
    • 2 years ago
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    3x^2-6x+3=0 ?

  2. jkev1
    • 2 years ago
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    whoops +3

  3. jkev1
    • 2 years ago
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    3x+6x+3=0

  4. Coolsector
    • 2 years ago
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    ax^2+bx+c = 0 \[\Delta=b^2-4ac\] if \[\Delta = 0\] then one real root if \[\Delta > 0\] two real roots if \[\Delta < 0\] no real roots

  5. Coolsector
    • 2 years ago
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    this is called discriminant

  6. jkev1
    • 2 years ago
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    so there is none?

  7. jkev1
    • 2 years ago
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    or two?

  8. Coolsector
    • 2 years ago
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    3x^2+6x+3=0 this is the equation ?

  9. jkev1
    • 2 years ago
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    3x+6x+3=0

  10. Coolsector
    • 2 years ago
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    no square ?

  11. Coolsector
    • 2 years ago
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    so what i said isnt relevant

  12. Coolsector
    • 2 years ago
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    9x + 3 =0 9x = -3 x = -3/9 one solution here

  13. Coolsector
    • 2 years ago
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    but are you sure there is no x^2 ?!

  14. jkev1
    • 2 years ago
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    positive thanks.

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