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pratu043
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But there's no 'z' in the equation, only x.

ParthKohli
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A RANDOM VARIABLE \(z\) HAZ POPPED UP ZOMG!!!

theredhead1617
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x = 29

joshuamcelwain
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Multiply 22 by 7...
5x=110
x=22 if thats what you want!

ParthKohli
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@theredhead1617
@joshuamcelwain
Are 22 and 29 the same numbers?

theredhead1617
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What?

ParthKohli
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@joshuamcelwain Do you think that \(22 \times = 110\)?

ParthKohli
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22 x 7^

theredhead1617
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No sorry I was wrong it's x = 29/5. That's what he wants.

hartnn
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22*7/5
no 1 esle is correct

hartnn
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154/5

joshuamcelwain
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Yeah woops,
22*7 is 154. You would then divide that by 5 to get 154/5 or 30.8

theredhead1617
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5x – 7 = 22
add 7 both sides
5x = 22+7 = 29
5x = 29
divide by 5 both sides
x = 29/5 = 5 4/5