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anonymous
 3 years ago
Solve these systems of equations 7x+2y= 3 and 14x4y=6 . I got y=3/2,
x= 6/7 am I right ?
anonymous
 3 years ago
Solve these systems of equations 7x+2y= 3 and 14x4y=6 . I got y=3/2, x= 6/7 am I right ?

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AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1hmm multiply first equation with 2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well yeah i did that multiplying it by 2 so that when i add it in the second question 14x and 14X cancel out (I'm using linear combinations here)

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1if thats the case both x and y cancels out!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0In the first equation you do 2y times 2 = 4y. Now in the 2nd equation you have 4y soo 4y+ 4y is 8y which means that the ys don't cancel out

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1infact both these lines are the same !!

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1take a look at the graph

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=solve+7x%2B2y%3D+3++and+14x4y%3D6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes I see...so there's something I'm doing wrong in my math here !

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0u were right they are the same line!

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1take a look at the question you have posted !!

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1:P yep makes sure u type the qns right :)
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