malutella
Solve these systems of equations 7x+2y= 3 and 14x4y=6 . I got y=3/2,
x= 6/7 am I right ?



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AravindG
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hmm multiply first equation with 2

AravindG
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14x+4y=6

AravindG
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14x+4y+6=0

malutella
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well yeah i did that multiplying it by 2 so that when i add it in the second question 14x and 14X cancel out (I'm using linear combinations here)

AravindG
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14x+4y6=0

malutella
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*equation

AravindG
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if thats the case both x and y cancels out!!

AravindG
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isnt it?

malutella
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In the first equation you do 2y times 2 = 4y. Now in the 2nd equation you have 4y soo 4y+ 4y is 8y which means that the ys don't cancel out

AravindG
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nt really :)

AravindG
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infact both these lines are the same !!

AravindG
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take a look at the graph


malutella
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yes I see...so there's something I'm doing wrong in my math here !

malutella
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u were right they are the same line!

AravindG
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take a look at the question you have posted !!

AravindG
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:P yep makes sure u type the qns right :)