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jkev1
Two pipes fill a storage tank in 9 hours. The larger pipe fills the tank three times as fast as the smaller one. How long would it take the larger pipe to fill the tank alone
let the smaller pipe rate be v so the larger will be 3v (v+3v) * 9 = 1 36v = 1 v=1/36 so in order to find t the time that it would take for the larger pipe all we haveto do is 3v * t = 1 you plug here the v that we found up there
lets do this together : 3v*t=1 3 * (1/36) * t = 1 (1/12) * t = 1 t = 12