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ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0\[x = {b \pm \sqrt{b^2  4ac} \over 2a}\]

jkev1
 2 years ago
Best ResponseYou've already chosen the best response.0thats not one of the options @ParthKohli

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0you should use what parthkohli wrote .. ax^2+bx+c =0 use what he wrote

jkev1
 2 years ago
Best ResponseYou've already chosen the best response.0it's not an option though @Coolsector

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0no .. look ax^2+bx+c =0 in your case a=2 b =8 c=1 now plug it into what parthkoli wrote and you will get the zeros ..

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0if you plug it into what partkholi wrote you get : \[\frac{ 8 \pm \sqrt{648} }{ 4 }\]
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