anonymous
  • anonymous
Use the quadratic formula to find the zeros of y=2x^2+8x+1
Mathematics
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anonymous
  • anonymous
Use the quadratic formula to find the zeros of y=2x^2+8x+1
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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ParthKohli
  • ParthKohli
\[x = {-b \pm \sqrt{b^2 - 4ac} \over 2a}\]
anonymous
  • anonymous
thats not one of the options @ParthKohli
anonymous
  • anonymous

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anonymous
  • anonymous
anonymous
  • anonymous
you should use what parthkohli wrote .. ax^2+bx+c =0 use what he wrote
anonymous
  • anonymous
it's not an option though @Coolsector
anonymous
  • anonymous
no .. look ax^2+bx+c =0 in your case a=2 b =8 c=1 now plug it into what parthkoli wrote and you will get the zeros ..
anonymous
  • anonymous
Look at this.
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anonymous
  • anonymous
anonymous
  • anonymous
if you plug it into what partkholi wrote you get : \[\frac{ -8 \pm \sqrt{64-8} }{ 4 }\]

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