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jkev1
Group Title
Use the quadratic formula to find the zeros of y=2x^2+8x+1
 one year ago
 one year ago
jkev1 Group Title
Use the quadratic formula to find the zeros of y=2x^2+8x+1
 one year ago
 one year ago

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ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
\[x = {b \pm \sqrt{b^2  4ac} \over 2a}\]
 one year ago

jkev1 Group TitleBest ResponseYou've already chosen the best response.0
thats not one of the options @ParthKohli
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.0
you should use what parthkohli wrote .. ax^2+bx+c =0 use what he wrote
 one year ago

jkev1 Group TitleBest ResponseYou've already chosen the best response.0
it's not an option though @Coolsector
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.0
no .. look ax^2+bx+c =0 in your case a=2 b =8 c=1 now plug it into what parthkoli wrote and you will get the zeros ..
 one year ago

jkev1 Group TitleBest ResponseYou've already chosen the best response.0
Look at this.
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.0
if you plug it into what partkholi wrote you get : \[\frac{ 8 \pm \sqrt{648} }{ 4 }\]
 one year ago
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