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jkev1
Group Title
Use the quadratic formula to find the zeros of y=2x^2+8x+1
 2 years ago
 2 years ago
jkev1 Group Title
Use the quadratic formula to find the zeros of y=2x^2+8x+1
 2 years ago
 2 years ago

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ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
\[x = {b \pm \sqrt{b^2  4ac} \over 2a}\]
 2 years ago

jkev1 Group TitleBest ResponseYou've already chosen the best response.0
thats not one of the options @ParthKohli
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.0
you should use what parthkohli wrote .. ax^2+bx+c =0 use what he wrote
 2 years ago

jkev1 Group TitleBest ResponseYou've already chosen the best response.0
it's not an option though @Coolsector
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.0
no .. look ax^2+bx+c =0 in your case a=2 b =8 c=1 now plug it into what parthkoli wrote and you will get the zeros ..
 2 years ago

jkev1 Group TitleBest ResponseYou've already chosen the best response.0
Look at this.
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.0
if you plug it into what partkholi wrote you get : \[\frac{ 8 \pm \sqrt{648} }{ 4 }\]
 2 years ago
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