## jkev1 2 years ago Use the quadratic formula to find the zeros of y=2x^2+8x+1

1. ParthKohli

$x = {-b \pm \sqrt{b^2 - 4ac} \over 2a}$

2. jkev1

thats not one of the options @ParthKohli

3. jkev1

@Coolsector

4. jkev1

@yahoo!

5. Coolsector

you should use what parthkohli wrote .. ax^2+bx+c =0 use what he wrote

6. jkev1

it's not an option though @Coolsector

7. Coolsector

no .. look ax^2+bx+c =0 in your case a=2 b =8 c=1 now plug it into what parthkoli wrote and you will get the zeros ..

8. jkev1

Look at this.

9. jkev1

@Coolsector

10. Coolsector

if you plug it into what partkholi wrote you get : $\frac{ -8 \pm \sqrt{64-8} }{ 4 }$