anonymous 3 years ago Use the quadratic formula to find the zeros of y=2x^2+8x+1

1. ParthKohli

$x = {-b \pm \sqrt{b^2 - 4ac} \over 2a}$

2. anonymous

thats not one of the options @ParthKohli

3. anonymous

@Coolsector

4. anonymous

@yahoo!

5. anonymous

you should use what parthkohli wrote .. ax^2+bx+c =0 use what he wrote

6. anonymous

it's not an option though @Coolsector

7. anonymous

no .. look ax^2+bx+c =0 in your case a=2 b =8 c=1 now plug it into what parthkoli wrote and you will get the zeros ..

8. anonymous

Look at this.

9. anonymous

@Coolsector

10. anonymous

if you plug it into what partkholi wrote you get : $\frac{ -8 \pm \sqrt{64-8} }{ 4 }$