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pachinkoboss

  • 3 years ago

is the inverse sine of sine of (-(4pi)/9)) equal pi/9?

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  1. Yahoo!
    • 3 years ago
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    sin(-x) = -sinx

  2. Yahoo!
    • 3 years ago
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    -sin^-1 (sin 4pie/9)

  3. Yahoo!
    • 3 years ago
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    so -4pie/9

  4. pachinkoboss
    • 3 years ago
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    Why not just -pi/9?

  5. pachinkoboss
    • 3 years ago
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    But pi/9 is in that range?

  6. myininaya
    • 3 years ago
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    Oh. Wait It is.

  7. pachinkoboss
    • 3 years ago
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    What is?

  8. myininaya
    • 3 years ago
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    lol. So yeah \[\frac{-4 \pi }{9} \in [\frac{-\pi}{2}, \frac{\pi}{2}] =>\sin^{-1}(\sin(\frac{-4 \pi}{9}))=\frac{-4 \pi}{9} \]

  9. myininaya
    • 3 years ago
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    \[-.444 \pi \in [-.5 \pi , .5 \pi]\] Since \[-.444 \in [-.5,.5]\]

  10. myininaya
    • 3 years ago
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    -4/9 is approximately -.444 :)

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