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chicagochica5

What is the remainder of (x^3 – 6x – 9x + 3) ÷ (x - 3)

  • one year ago
  • one year ago

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  1. nphuongsun93
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    do you know how to divide them?

    • one year ago
  2. chicagochica5
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    no :(

    • one year ago
  3. chicagochica5
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    @nphuongsun93 and you help me?

    • one year ago
  4. nphuongsun93
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    woops sorry i'm here, 1 sec

    • one year ago
  5. nphuongsun93
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    first let me confirm is it (x^3 – 6x – 9x + 3) ÷ (x - 3) OR (x^3 – 6x^2 – 9x + 3) ÷ (x - 3) ^^^^^

    • one year ago
  6. chicagochica5
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    (x^3 – 6x – 9x + 3) ÷ (x - 3) this is correct

    • one year ago
  7. nphuongsun93
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    then first simplify x^3 - 6x - 9x + 3 = x^3 - 15x + 3|dw:1349205093592:dw|

    • one year ago
  8. nphuongsun93
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    |dw:1349205145845:dw|

    • one year ago
  9. nphuongsun93
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    |dw:1349205201562:dw|

    • one year ago
  10. nphuongsun93
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    |dw:1349205284237:dw| (x^3 - 15x + 3) ÷ (x - 3) = x^2 + 3x - 6 remainder - 15

    • one year ago
  11. chicagochica5
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    -15 or -51?

    • one year ago
  12. chicagochica5
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    theses are my choices: A: -51

    • one year ago
  13. chicagochica5
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    B: -51 ------- x - 3

    • one year ago
  14. chicagochica5
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    C: -17 ------- x

    • one year ago
  15. chicagochica5
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    D: -17 -------- x - 3

    • one year ago
  16. chicagochica5
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    @nphuongsun93 do you know?

    • one year ago
  17. nphuongsun93
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    oh i see -_- this is why i asked you if it's (x^3 – 6x – 9x + 3) ÷ (x - 3) OR (x^3 – 6x^2 – 9x + 3) ÷ (x - 3) you missed a ^2 in the 6x if it's (x^3 – 6x^2 – 9x + 3) ÷ (x - 3), then the remainder is - 51/(x-3)

    • one year ago
  18. chicagochica5
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    On my paper its only 6x @nphuongsun93

    • one year ago
  19. chicagochica5
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    I guess it was a misprint on there end. thanks @nphuongsun93

    • one year ago
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