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What is the remainder of (x^3 – 6x – 9x + 3) ÷ (x - 3)

Mathematics
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do you know how to divide them?
no :(
@nphuongsun93 and you help me?

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Other answers:

woops sorry i'm here, 1 sec
first let me confirm is it (x^3 – 6x – 9x + 3) ÷ (x - 3) OR (x^3 – 6x^2 – 9x + 3) ÷ (x - 3) ^^^^^
(x^3 – 6x – 9x + 3) ÷ (x - 3) this is correct
then first simplify x^3 - 6x - 9x + 3 = x^3 - 15x + 3|dw:1349205093592:dw|
|dw:1349205145845:dw|
|dw:1349205201562:dw|
|dw:1349205284237:dw| (x^3 - 15x + 3) ÷ (x - 3) = x^2 + 3x - 6 remainder - 15
-15 or -51?
theses are my choices: A: -51
B: -51 ------- x - 3
C: -17 ------- x
D: -17 -------- x - 3
@nphuongsun93 do you know?
oh i see -_- this is why i asked you if it's (x^3 – 6x – 9x + 3) ÷ (x - 3) OR (x^3 – 6x^2 – 9x + 3) ÷ (x - 3) you missed a ^2 in the 6x if it's (x^3 – 6x^2 – 9x + 3) ÷ (x - 3), then the remainder is - 51/(x-3)
On my paper its only 6x @nphuongsun93
I guess it was a misprint on there end. thanks @nphuongsun93

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