chicagochica5
What is the remainder of (x^3 – 6x – 9x + 3) ÷ (x - 3)
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nphuongsun93
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do you know how to divide them?
chicagochica5
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no :(
chicagochica5
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@nphuongsun93 and you help me?
nphuongsun93
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woops sorry i'm here, 1 sec
nphuongsun93
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first let me confirm is it (x^3 – 6x – 9x + 3) ÷ (x - 3) OR (x^3 – 6x^2 – 9x + 3) ÷ (x - 3)
^^^^^
chicagochica5
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(x^3 – 6x – 9x + 3) ÷ (x - 3) this is correct
nphuongsun93
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then first simplify
x^3 - 6x - 9x + 3 = x^3 - 15x + 3|dw:1349205093592:dw|
nphuongsun93
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|dw:1349205145845:dw|
nphuongsun93
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|dw:1349205201562:dw|
nphuongsun93
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|dw:1349205284237:dw|
(x^3 - 15x + 3) ÷ (x - 3) = x^2 + 3x - 6 remainder - 15
chicagochica5
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-15 or -51?
chicagochica5
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theses are my choices:
A: -51
chicagochica5
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B: -51
-------
x - 3
chicagochica5
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C:
-17
-------
x
chicagochica5
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D:
-17
--------
x - 3
chicagochica5
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@nphuongsun93 do you know?
nphuongsun93
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oh i see -_-
this is why i asked you if it's
(x^3 – 6x – 9x + 3) ÷ (x - 3) OR (x^3 – 6x^2 – 9x + 3) ÷ (x - 3)
you missed a ^2 in the 6x
if it's (x^3 – 6x^2 – 9x + 3) ÷ (x - 3), then the remainder is - 51/(x-3)
chicagochica5
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On my paper its only 6x @nphuongsun93
chicagochica5
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I guess it was a misprint on there end. thanks @nphuongsun93