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Remains? Remainder?

all I number it present as this a/3 and a can be (0,1,2,3...n)

yes you got it by the way (m+2)^2=m^2+4m+4

Great! Oh, of course it's, my bad ;)

We did answer the remain will be all Interger #

Well you can only get remainders of 0, 1, and 2... that's obvious.

What about the 4 I got above when n= (m+2) -> m^2+4m+4 ?

Okey I get it, thanks a lot! :)