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spose you ahve 2 integers; if you take the larger of the two, and add it to the smaller ofthe two; you are essentially adding the two numbers togheter
max(8,3) + min(8,3) = 8 + 3 and all that for the cost of tuition :/
and there was even a case by case proof for it
show proof? :D
lol, i cant, it burnt out to many synapses just trying to pretend i was interested
take 2 integers; x and y case 1; if x < y max(x,y) = y min(x,y) = x max(x,y) +min(x,y) = y + x case 2; if x > y max(x,y) = x min(x,y) = y max(x,y) +min(x,y) = x + y; which equals y + x case 2; if x = y max(y,y) = y min(x,x) = x max(x,y) +min(x,y) = y + x
<3 thank you although i have a question is this all you learn in number theory?
haha .. then till now you wasted your money!!
no, the other day we learned that if a is not a factor of b, but is a factor of c, then a divides b*c
therefore; since 3 is not a factor of 5; but is a factor of 9; then 3 is a factor of 5*9
oh it feels like a whole lotta wasted money and time at the moment :)
it does ... this is the basics. try taking mit course on number theory. though i never;ve taken it yet. i think it's worth.
yeah, these undergraduate courses make me feel like im back in kindergarten
well ... i never took number theory class. though i had read some part of it in analysis and algebra. I think it's quite interesting and though (this might be lack of experience)
the class seems to revolve around prime numbers. On the last test, we had to determine oif some huge number was prime or not; and the only way we had to check it was by seeing of the 50 primes less than its sqrt divided it. In the end, it was prime
im outta here fer today; enjoy the night :)
catch ya later :)
90% of the topic here I'm not familiar http://ocw.mit.edu/courses/mathematics/18-785-analytic-number-theory-spring-2007/syllabus/
looks like worth doing it!!