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patbatE21
The sum of 12 times the larger number and 11 times the smaller is -36. The difference of 12 times the larger and 7 times the smaller is 36. Find the numbers.
let \(x\) and \(y\) the two numbers we r looking for. and suppose that \(x>y\). then \[ \large 12x+11y=-36 \] and \[ \large 12x-7y=36 \]
alright then should I move forward with the addition method?
u have a linear system \[ \large \begin{cases} 12x+11y=-36\\ 12x-7y=36 \end{cases} \]
use whichever method u want to solve it.