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xRAWRRx3 Group Title

Find the negative root of 6x^2 - 5y = 0. can someone please explain how to get the answer please?

  • one year ago
  • one year ago

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  1. goformit100 Group Title
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    |dw:1349232991716:dw|

    • one year ago
  2. xRAWRRx3 Group Title
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    and what does that find?

    • one year ago
  3. xRAWRRx3 Group Title
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    the root?

    • one year ago
  4. Ashley1593 Group Title
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    \[5 \pm \sqrt{(6^2+(-5)^2 -4(6)(0))/2(6)}= 1 and -0.234\]

    • one year ago
  5. xRAWRRx3 Group Title
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    I'm sorry but II don't know how to do that...

    • one year ago
  6. Ashley1593 Group Title
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    its the quadratic formula where y=Ax^2 + Bx + C

    • one year ago
  7. xRAWRRx3 Group Title
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    oh, I'm sorry, I didn't really learn it yet so I can't really use it.

    • one year ago
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