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MathSofiya
Group Title
Statistics:
\[\mu=28\]
\[\sigma=5\]
If \[P(z\le z_0)=0.12\]
How do I use the attached table to come to the conclusion that \[z_0=1.175\]?
 one year ago
 one year ago
MathSofiya Group Title
Statistics: \[\mu=28\] \[\sigma=5\] If \[P(z\le z_0)=0.12\] How do I use the attached table to come to the conclusion that \[z_0=1.175\]?
 one year ago
 one year ago

This Question is Closed

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
look up .12 in the middle of the table
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
or the numbers closest to .12
 one year ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.0
You mean here?
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
no...the middle of the table...middle of the paper
 one year ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.0
No I think you mean here
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
middle! ... don't look along the edge yet
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
yes...but there is another number that is really close to .12
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
yes...what are the z values for those 2 numbers
 one year ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.0
but how did they come to the conclusion that z_0=1.175?
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
answer my last question first
 one year ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.0
1.1 and .07 and .08....ah I see Therefore 1.75 since it between .1190 and .1210
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
1.17 and 1.18 take average of the two gives 1.175
 one year ago
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