A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Statistics:
\[\mu=28\]
\[\sigma=5\]
If \[P(z\le z_0)=0.12\]
How do I use the attached table to come to the conclusion that \[z_0=1.175\]?
anonymous
 4 years ago
Statistics: \[\mu=28\] \[\sigma=5\] If \[P(z\le z_0)=0.12\] How do I use the attached table to come to the conclusion that \[z_0=1.175\]?

This Question is Closed

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.1look up .12 in the middle of the table

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.1or the numbers closest to .12

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.1no...the middle of the table...middle of the paper

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No I think you mean here

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.1middle! ... don't look along the edge yet

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.1yes...but there is another number that is really close to .12

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.1yes...what are the z values for those 2 numbers

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but how did they come to the conclusion that z_0=1.175?

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.1answer my last question first

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01.1 and .07 and .08....ah I see Therefore 1.75 since it between .1190 and .1210

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.11.17 and 1.18 take average of the two gives 1.175
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.