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MathSofiya Group Title

Statistics: \[\mu=28\] \[\sigma=5\] If \[P(z\le z_0)=0.12\] How do I use the attached table to come to the conclusion that \[z_0=-1.175\]?

  • 2 years ago
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  1. MathSofiya Group Title
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    • 2 years ago
  2. Zarkon Group Title
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    look up .12 in the middle of the table

    • 2 years ago
  3. Zarkon Group Title
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    or the numbers closest to .12

    • 2 years ago
  4. MathSofiya Group Title
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    You mean here?

    • 2 years ago
  5. Zarkon Group Title
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    no...the middle of the table...middle of the paper

    • 2 years ago
  6. MathSofiya Group Title
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    No I think you mean here

    • 2 years ago
  7. MathSofiya Group Title
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    right?

    • 2 years ago
  8. Zarkon Group Title
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    no

    • 2 years ago
  9. MathSofiya Group Title
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    Where?

    • 2 years ago
  10. Zarkon Group Title
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    middle! ... don't look along the edge yet

    • 2 years ago
  11. MathSofiya Group Title
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    here?

    • 2 years ago
  12. Zarkon Group Title
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    yes...but there is another number that is really close to .12

    • 2 years ago
  13. MathSofiya Group Title
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    .1190

    • 2 years ago
  14. Zarkon Group Title
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    yes...what are the z values for those 2 numbers

    • 2 years ago
  15. MathSofiya Group Title
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    but how did they come to the conclusion that z_0=-1.175?

    • 2 years ago
  16. Zarkon Group Title
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    answer my last question first

    • 2 years ago
  17. MathSofiya Group Title
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    -1.1 and .07 and .08....ah I see Therefore -1.75 since it between .1190 and .1210

    • 2 years ago
  18. Zarkon Group Title
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    -1.17 and -1.18 take average of the two gives -1.175

    • 2 years ago
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