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Mathhelp346

  • 3 years ago

Write an equation that contains the given point and is perpendicular to the given line: (4,-1), y=-8

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  1. Mathhelp346
    • 3 years ago
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    I tried \[y-y _{1}=m(x-x _{1})\] but i would always get a value for y which isnt right

  2. tejasree
    • 3 years ago
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    I think it is x = 4, thats the equation

  3. Mathhelp346
    • 3 years ago
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    how did you get that

  4. tejasree
    • 3 years ago
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    y = -8 is a horizontal line, the line is perpendicualr to a vertical line, get it?

  5. Mathhelp346
    • 3 years ago
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    yea

  6. tejasree
    • 3 years ago
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    so with a vertical line, x will equal one number, in this case, it is 4, always 4 for any y, so its x = 4, did i confuse u?

  7. Mathhelp346
    • 3 years ago
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    well how did you get x=4?

  8. tejasree
    • 3 years ago
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    it said that it has to contain (4, -1) so that's how I figured that x has to equal 4

  9. tejasree
    • 3 years ago
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    Some points of x = 4 are: (4,2)(4,8),(4,-6).......so one....understand?

  10. Mathhelp346
    • 3 years ago
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    so you just took the 4 from the pair?

  11. tejasree
    • 3 years ago
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    yup, if i included another x-value along with the pair we have, its not going to be perpendicular, that's why

  12. Mathhelp346
    • 3 years ago
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    oh ok thanks

  13. tejasree
    • 3 years ago
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    yea! Thanks :)

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