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ebydaqueen17

  • 3 years ago

x=2 2x-y=4 3x+2y-2z=4 solve by substitution

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  1. justicebeaver
    • 3 years ago
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    If x=2, put x into the second equation. 2(2)-y=4 4-y=4 -y=0 y=0. Now you know y. Plug x and y into the last equation. 3(2)+2(0)-2z=4 6+0-2z=4 -2z=-2 z=1. x=2, y=0, z=1.

  2. ebydaqueen17
    • 3 years ago
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    oh ok thanks...

  3. justicebeaver
    • 3 years ago
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    Yep. :)

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