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ebydaqueen17
x=2 2x-y=4 3x+2y-2z=4 solve by substitution
If x=2, put x into the second equation. 2(2)-y=4 4-y=4 -y=0 y=0. Now you know y. Plug x and y into the last equation. 3(2)+2(0)-2z=4 6+0-2z=4 -2z=-2 z=1. x=2, y=0, z=1.