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UsukiDoll

Quick question what is the antiderivative of 3sinxcosx?

  • one year ago
  • one year ago

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  1. UsukiDoll
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    wouldn't my u be sinx and du cosx?

    • one year ago
  2. mathslover
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    Anti derivative .. hmn wait

    • one year ago
  3. mathslover
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    Can we say ; antiderivative as "integration" also?

    • one year ago
  4. mayankdevnani
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    @mathslover yes we can

    • one year ago
  5. mathslover
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    @.Sam. Please let me try?

    • one year ago
  6. UsukiDoll
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    I just need to know what the antiderivate of 3sinxcosx is and yes I am integrating from crud hold up let me find it. Got hazelnut on my fingers

    • one year ago
  7. mathslover
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    is it : \(\frac{-3}{2}cos^2x\) ?

    • one year ago
  8. mathslover
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    OH + C there also

    • one year ago
  9. .Sam.
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    \[\int\limits_{}^{}3sinxcosx~dx \\ \\ Let~u=sinx \\ \\du=cosx~dx \\ \\ Then, \\ \\ \int\limits_{}^{}3u~du \\ \\ Integrate\]

    • one year ago
  10. mathslover
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    @UsukiDoll you were at right process.

    • one year ago
  11. .Sam.
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    @mathslover oh sry didn't see your comment there.

    • one year ago
  12. mathslover
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    :) No problem @.Sam. , it is so nice of you to even say "sry" no mistake of yours' . Though, can you tell whether I am correct or not (scroll up to see my answer)

    • one year ago
  13. mayankdevnani
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    \[\int\limits_{0}^{\frac{\pi}{2}}\] 3cos(x)sin(x)dx=\[\frac{3}{2}\]

    • one year ago
  14. UsukiDoll
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    I need the antiderivative of 3sinxcosx integrating from pi/2 to 0. umm that's what I did. like u sinx du cosx and then it's 3/2 u^2 but for some reason my manual has it at 3/2 sin2t. ummm WHAT!

    • one year ago
  15. mayankdevnani
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    @UsukiDoll ok got it

    • one year ago
  16. mayankdevnani
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    @mathslover am i right

    • one year ago
  17. UsukiDoll
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    sin^2t maybe but sin2t? what the heck

    • one year ago
  18. mathslover
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    ==lol

    • one year ago
  19. .Sam.
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    @mathslover yes you are

    • one year ago
  20. ByteMe
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    why not just u=sinx so du=cosxdx ???

    • one year ago
  21. UsukiDoll
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    ummm that's what I did bytemr

    • one year ago
  22. UsukiDoll
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    oops yes a =0 b = pi/2

    • one year ago
  23. ByteMe
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    lol.... you said my name...

    • one year ago
  24. UsukiDoll
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    loloolol

    • one year ago
  25. UsukiDoll
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    I could've sworn it was like this... |dw:1349253100916:dw|

    • one year ago
  26. hartnn
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    3sinx cos x = 3/2 sin 2x does this ring the bell ?

    • one year ago
  27. UsukiDoll
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    Why is it sinx 2x?!?!?!?!?!?!?!!?

    • one year ago
  28. UsukiDoll
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    is there an identity that I missed @hartnn

    • one year ago
  29. hartnn
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    double angle formula: sin 2x = 2 sin x cos x cos 2x = cos^2 x- sin^2 x = 2cos^2x -1 = 1-2sin^2 x

    • one year ago
  30. UsukiDoll
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    yeah but that 2sinxcosx not 3sinxcosx and why is the 2 below the 3 in this one?

    • one year ago
  31. hartnn
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    @mathslover you were typing something ? 3sin x cos x = 3/2 (2sin x cos x) = 3/2 sin 2x

    • one year ago
  32. hartnn
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    its antiderivative will be -3/4 cos 2x

    • one year ago
  33. UsukiDoll
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    again what I don't understand is why the 3/2? the problem is 3sinxcosx. There is no 2sinxcosx. so what Do i DO?

    • one year ago
  34. hartnn
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    so u did not understand this ? 3sin x cos x = 3/2 (2sin x cos x) i just multiplied and divided by 2

    • one year ago
  35. UsukiDoll
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    ohhhhh..... -___-|dw:1349253933438:dw|

    • one year ago
  36. UsukiDoll
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    that's legal? multiplying 2 and dividing 2?

    • one year ago
  37. hartnn
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    absolutely! because 2 is constant.

    • one year ago
  38. UsukiDoll
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    O______O!

    • one year ago
  39. UsukiDoll
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    ummm what math class is this normally in? Is it in trig?

    • one year ago
  40. hartnn
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    those double angle formulas? in trignometry..

    • one year ago
  41. UsukiDoll
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    no about the 3/2 2sinxcosx

    • one year ago
  42. hartnn
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    its general, no particular topic, u can do that anytime, anywhere...

    • one year ago
  43. UsukiDoll
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    THE HECK?

    • one year ago
  44. UsukiDoll
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    I got one more...so I'm opening a new question.

    • one year ago
  45. hartnn
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    ok.

    • one year ago
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