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UsukiDoll
 2 years ago
Best ResponseYou've already chosen the best response.1wouldn't my u be sinx and du cosx?

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2Anti derivative .. hmn wait

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2Can we say ; antiderivative as "integration" also?

mayankdevnani
 2 years ago
Best ResponseYou've already chosen the best response.0@mathslover yes we can

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2@.Sam. Please let me try?

UsukiDoll
 2 years ago
Best ResponseYou've already chosen the best response.1I just need to know what the antiderivate of 3sinxcosx is and yes I am integrating from crud hold up let me find it. Got hazelnut on my fingers

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2is it : \(\frac{3}{2}cos^2x\) ?

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{}^{}3sinxcosx~dx \\ \\ Let~u=sinx \\ \\du=cosx~dx \\ \\ Then, \\ \\ \int\limits_{}^{}3u~du \\ \\ Integrate\]

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2@UsukiDoll you were at right process.

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.1@mathslover oh sry didn't see your comment there.

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2:) No problem @.Sam. , it is so nice of you to even say "sry" no mistake of yours' . Though, can you tell whether I am correct or not (scroll up to see my answer)

mayankdevnani
 2 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{\frac{\pi}{2}}\] 3cos(x)sin(x)dx=\[\frac{3}{2}\]

UsukiDoll
 2 years ago
Best ResponseYou've already chosen the best response.1I need the antiderivative of 3sinxcosx integrating from pi/2 to 0. umm that's what I did. like u sinx du cosx and then it's 3/2 u^2 but for some reason my manual has it at 3/2 sin2t. ummm WHAT!

mayankdevnani
 2 years ago
Best ResponseYou've already chosen the best response.0@UsukiDoll ok got it

mayankdevnani
 2 years ago
Best ResponseYou've already chosen the best response.0@mathslover am i right

UsukiDoll
 2 years ago
Best ResponseYou've already chosen the best response.1sin^2t maybe but sin2t? what the heck

ByteMe
 2 years ago
Best ResponseYou've already chosen the best response.1why not just u=sinx so du=cosxdx ???

UsukiDoll
 2 years ago
Best ResponseYou've already chosen the best response.1ummm that's what I did bytemr

UsukiDoll
 2 years ago
Best ResponseYou've already chosen the best response.1oops yes a =0 b = pi/2

ByteMe
 2 years ago
Best ResponseYou've already chosen the best response.1lol.... you said my name...

UsukiDoll
 2 years ago
Best ResponseYou've already chosen the best response.1I could've sworn it was like this... dw:1349253100916:dw

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.03sinx cos x = 3/2 sin 2x does this ring the bell ?

UsukiDoll
 2 years ago
Best ResponseYou've already chosen the best response.1Why is it sinx 2x?!?!?!?!?!?!?!!?

UsukiDoll
 2 years ago
Best ResponseYou've already chosen the best response.1is there an identity that I missed @hartnn

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0double angle formula: sin 2x = 2 sin x cos x cos 2x = cos^2 x sin^2 x = 2cos^2x 1 = 12sin^2 x

UsukiDoll
 2 years ago
Best ResponseYou've already chosen the best response.1yeah but that 2sinxcosx not 3sinxcosx and why is the 2 below the 3 in this one?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0@mathslover you were typing something ? 3sin x cos x = 3/2 (2sin x cos x) = 3/2 sin 2x

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0its antiderivative will be 3/4 cos 2x

UsukiDoll
 2 years ago
Best ResponseYou've already chosen the best response.1again what I don't understand is why the 3/2? the problem is 3sinxcosx. There is no 2sinxcosx. so what Do i DO?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0so u did not understand this ? 3sin x cos x = 3/2 (2sin x cos x) i just multiplied and divided by 2

UsukiDoll
 2 years ago
Best ResponseYou've already chosen the best response.1ohhhhh..... ___dw:1349253933438:dw

UsukiDoll
 2 years ago
Best ResponseYou've already chosen the best response.1that's legal? multiplying 2 and dividing 2?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0absolutely! because 2 is constant.

UsukiDoll
 2 years ago
Best ResponseYou've already chosen the best response.1ummm what math class is this normally in? Is it in trig?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0those double angle formulas? in trignometry..

UsukiDoll
 2 years ago
Best ResponseYou've already chosen the best response.1no about the 3/2 2sinxcosx

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0its general, no particular topic, u can do that anytime, anywhere...

UsukiDoll
 2 years ago
Best ResponseYou've already chosen the best response.1I got one more...so I'm opening a new question.
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