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UsukiDoll
Group Title
Quick question what is the antiderivative of 3sinxcosx?
 2 years ago
 2 years ago
UsukiDoll Group Title
Quick question what is the antiderivative of 3sinxcosx?
 2 years ago
 2 years ago

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UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
wouldn't my u be sinx and du cosx?
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
Anti derivative .. hmn wait
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
Can we say ; antiderivative as "integration" also?
 2 years ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
@mathslover yes we can
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
@.Sam. Please let me try?
 2 years ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
I just need to know what the antiderivate of 3sinxcosx is and yes I am integrating from crud hold up let me find it. Got hazelnut on my fingers
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
is it : \(\frac{3}{2}cos^2x\) ?
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
OH + C there also
 2 years ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.1
\[\int\limits_{}^{}3sinxcosx~dx \\ \\ Let~u=sinx \\ \\du=cosx~dx \\ \\ Then, \\ \\ \int\limits_{}^{}3u~du \\ \\ Integrate\]
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
@UsukiDoll you were at right process.
 2 years ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.1
@mathslover oh sry didn't see your comment there.
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
:) No problem @.Sam. , it is so nice of you to even say "sry" no mistake of yours' . Though, can you tell whether I am correct or not (scroll up to see my answer)
 2 years ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits_{0}^{\frac{\pi}{2}}\] 3cos(x)sin(x)dx=\[\frac{3}{2}\]
 2 years ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
I need the antiderivative of 3sinxcosx integrating from pi/2 to 0. umm that's what I did. like u sinx du cosx and then it's 3/2 u^2 but for some reason my manual has it at 3/2 sin2t. ummm WHAT!
 2 years ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
@UsukiDoll ok got it
 2 years ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
@mathslover am i right
 2 years ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
sin^2t maybe but sin2t? what the heck
 2 years ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.1
@mathslover yes you are
 2 years ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
why not just u=sinx so du=cosxdx ???
 2 years ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
ummm that's what I did bytemr
 2 years ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
oops yes a =0 b = pi/2
 2 years ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
lol.... you said my name...
 2 years ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
I could've sworn it was like this... dw:1349253100916:dw
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
3sinx cos x = 3/2 sin 2x does this ring the bell ?
 2 years ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
Why is it sinx 2x?!?!?!?!?!?!?!!?
 2 years ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
is there an identity that I missed @hartnn
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
double angle formula: sin 2x = 2 sin x cos x cos 2x = cos^2 x sin^2 x = 2cos^2x 1 = 12sin^2 x
 2 years ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
yeah but that 2sinxcosx not 3sinxcosx and why is the 2 below the 3 in this one?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
@mathslover you were typing something ? 3sin x cos x = 3/2 (2sin x cos x) = 3/2 sin 2x
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
its antiderivative will be 3/4 cos 2x
 2 years ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
again what I don't understand is why the 3/2? the problem is 3sinxcosx. There is no 2sinxcosx. so what Do i DO?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
so u did not understand this ? 3sin x cos x = 3/2 (2sin x cos x) i just multiplied and divided by 2
 2 years ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
ohhhhh..... ___dw:1349253933438:dw
 2 years ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
that's legal? multiplying 2 and dividing 2?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
absolutely! because 2 is constant.
 2 years ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
O______O!
 2 years ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
ummm what math class is this normally in? Is it in trig?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
those double angle formulas? in trignometry..
 2 years ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
no about the 3/2 2sinxcosx
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
its general, no particular topic, u can do that anytime, anywhere...
 2 years ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
THE HECK?
 2 years ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
I got one more...so I'm opening a new question.
 2 years ago
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