Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

UsukiDoll

  • 3 years ago

Quick question what is the antiderivative of 3sinxcosx?

  • This Question is Closed
  1. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    wouldn't my u be sinx and du cosx?

  2. mathslover
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Anti derivative .. hmn wait

  3. mathslover
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Can we say ; antiderivative as "integration" also?

  4. mayankdevnani
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @mathslover yes we can

  5. mathslover
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    @.Sam. Please let me try?

  6. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I just need to know what the antiderivate of 3sinxcosx is and yes I am integrating from crud hold up let me find it. Got hazelnut on my fingers

  7. mathslover
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    is it : \(\frac{-3}{2}cos^2x\) ?

  8. mathslover
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    OH + C there also

  9. .Sam.
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\int\limits_{}^{}3sinxcosx~dx \\ \\ Let~u=sinx \\ \\du=cosx~dx \\ \\ Then, \\ \\ \int\limits_{}^{}3u~du \\ \\ Integrate\]

  10. mathslover
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    @UsukiDoll you were at right process.

  11. .Sam.
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @mathslover oh sry didn't see your comment there.

  12. mathslover
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    :) No problem @.Sam. , it is so nice of you to even say "sry" no mistake of yours' . Though, can you tell whether I am correct or not (scroll up to see my answer)

  13. mayankdevnani
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\int\limits_{0}^{\frac{\pi}{2}}\] 3cos(x)sin(x)dx=\[\frac{3}{2}\]

  14. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I need the antiderivative of 3sinxcosx integrating from pi/2 to 0. umm that's what I did. like u sinx du cosx and then it's 3/2 u^2 but for some reason my manual has it at 3/2 sin2t. ummm WHAT!

  15. mayankdevnani
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @UsukiDoll ok got it

  16. mayankdevnani
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @mathslover am i right

  17. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    sin^2t maybe but sin2t? what the heck

  18. mathslover
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    ==lol

  19. .Sam.
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @mathslover yes you are

  20. ByteMe
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    why not just u=sinx so du=cosxdx ???

  21. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ummm that's what I did bytemr

  22. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    oops yes a =0 b = pi/2

  23. ByteMe
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    lol.... you said my name...

  24. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    loloolol

  25. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I could've sworn it was like this... |dw:1349253100916:dw|

  26. hartnn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    3sinx cos x = 3/2 sin 2x does this ring the bell ?

  27. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Why is it sinx 2x?!?!?!?!?!?!?!!?

  28. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    is there an identity that I missed @hartnn

  29. hartnn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    double angle formula: sin 2x = 2 sin x cos x cos 2x = cos^2 x- sin^2 x = 2cos^2x -1 = 1-2sin^2 x

  30. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yeah but that 2sinxcosx not 3sinxcosx and why is the 2 below the 3 in this one?

  31. hartnn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @mathslover you were typing something ? 3sin x cos x = 3/2 (2sin x cos x) = 3/2 sin 2x

  32. hartnn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    its antiderivative will be -3/4 cos 2x

  33. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    again what I don't understand is why the 3/2? the problem is 3sinxcosx. There is no 2sinxcosx. so what Do i DO?

  34. hartnn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so u did not understand this ? 3sin x cos x = 3/2 (2sin x cos x) i just multiplied and divided by 2

  35. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ohhhhh..... -___-|dw:1349253933438:dw|

  36. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    that's legal? multiplying 2 and dividing 2?

  37. hartnn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    absolutely! because 2 is constant.

  38. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    O______O!

  39. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ummm what math class is this normally in? Is it in trig?

  40. hartnn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    those double angle formulas? in trignometry..

  41. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    no about the 3/2 2sinxcosx

  42. hartnn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    its general, no particular topic, u can do that anytime, anywhere...

  43. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    THE HECK?

  44. UsukiDoll
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I got one more...so I'm opening a new question.

  45. hartnn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok.

  46. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy