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UsukiDoll
Group Title
Quick question what is the antiderivative of 3sinxcosx?
 one year ago
 one year ago
UsukiDoll Group Title
Quick question what is the antiderivative of 3sinxcosx?
 one year ago
 one year ago

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UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
wouldn't my u be sinx and du cosx?
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
Anti derivative .. hmn wait
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
Can we say ; antiderivative as "integration" also?
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
@mathslover yes we can
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
@.Sam. Please let me try?
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
I just need to know what the antiderivate of 3sinxcosx is and yes I am integrating from crud hold up let me find it. Got hazelnut on my fingers
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
is it : \(\frac{3}{2}cos^2x\) ?
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
OH + C there also
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.1
\[\int\limits_{}^{}3sinxcosx~dx \\ \\ Let~u=sinx \\ \\du=cosx~dx \\ \\ Then, \\ \\ \int\limits_{}^{}3u~du \\ \\ Integrate\]
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
@UsukiDoll you were at right process.
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.1
@mathslover oh sry didn't see your comment there.
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
:) No problem @.Sam. , it is so nice of you to even say "sry" no mistake of yours' . Though, can you tell whether I am correct or not (scroll up to see my answer)
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits_{0}^{\frac{\pi}{2}}\] 3cos(x)sin(x)dx=\[\frac{3}{2}\]
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
I need the antiderivative of 3sinxcosx integrating from pi/2 to 0. umm that's what I did. like u sinx du cosx and then it's 3/2 u^2 but for some reason my manual has it at 3/2 sin2t. ummm WHAT!
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
@UsukiDoll ok got it
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
@mathslover am i right
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
sin^2t maybe but sin2t? what the heck
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.1
@mathslover yes you are
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
why not just u=sinx so du=cosxdx ???
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
ummm that's what I did bytemr
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
oops yes a =0 b = pi/2
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
lol.... you said my name...
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
loloolol
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
I could've sworn it was like this... dw:1349253100916:dw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
3sinx cos x = 3/2 sin 2x does this ring the bell ?
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
Why is it sinx 2x?!?!?!?!?!?!?!!?
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
is there an identity that I missed @hartnn
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
double angle formula: sin 2x = 2 sin x cos x cos 2x = cos^2 x sin^2 x = 2cos^2x 1 = 12sin^2 x
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
yeah but that 2sinxcosx not 3sinxcosx and why is the 2 below the 3 in this one?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
@mathslover you were typing something ? 3sin x cos x = 3/2 (2sin x cos x) = 3/2 sin 2x
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
its antiderivative will be 3/4 cos 2x
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
again what I don't understand is why the 3/2? the problem is 3sinxcosx. There is no 2sinxcosx. so what Do i DO?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
so u did not understand this ? 3sin x cos x = 3/2 (2sin x cos x) i just multiplied and divided by 2
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
ohhhhh..... ___dw:1349253933438:dw
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
that's legal? multiplying 2 and dividing 2?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
absolutely! because 2 is constant.
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
O______O!
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
ummm what math class is this normally in? Is it in trig?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
those double angle formulas? in trignometry..
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
no about the 3/2 2sinxcosx
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
its general, no particular topic, u can do that anytime, anywhere...
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
THE HECK?
 one year ago

UsukiDoll Group TitleBest ResponseYou've already chosen the best response.1
I got one more...so I'm opening a new question.
 one year ago
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