## dan18 Group Title The maximum value of the function one year ago one year ago

1. hartnn Group Title

can be found by taking the derivative of that funtion and equating it to 0.

2. dan18 Group Title

y=$\sqrt{2-x}$

3. hartnn Group Title

so did u find y' ?

4. dan18 Group Title

y=-4[\sqrt{2-x}\]

5. hartnn Group Title

could u differentiate y ?

6. miteshchvm Group Title

differentiate the function, then put the differentiated equation = 0 you will have either one answer or 2, if you get two answers, the one which has negative value will be the maximum value of the function ;)

7. dan18 Group Title

is it the y value?

8. hartnn Group Title

have u learned to differentiate x^n ?

9. dan18 Group Title

y'= nx^n-1

10. hartnn Group Title

so couldn't u differentiate y=-4 sqrt(2-x) ??

11. dan18 Group Title

does the max. value asked here is the x or the y value?

12. hartnn Group Title

y value

13. dan18 Group Title

y'= 2/(2-x)^-(1/2)

14. akash_809 Group Title

@dan18 , the correct way is to differentiate and equate to zero , but just by looking at this question once can tell it's maximum value is infinity for x=-infinity....pretty weird question i guess...are u sure u hv typed the question correctly

15. hartnn Group Title

wouldn't it be y'= 2/((2-x)^(1/2))

16. dan18 Group Title

I get x=2 @ y', then subts. it to the eq. does the max. value = 0?

17. akash_809 Group Title

@dan18 is the question correct ?

18. hartnn Group Title

but actual answer is infact Max. value = 0 when x=2 http://www.wolframalpha.com/input/?i=y%3D-4+sqrt%282-x%29

19. dan18 Group Title

$y=-4\sqrt{2-x}$

20. dan18 Group Title

thak you guys!

21. akash_809 Group Title

now u hv got the correct question, yes the max would be zero