Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

hartnn Group TitleBest ResponseYou've already chosen the best response.1
can be found by taking the derivative of that funtion and equating it to 0.
 one year ago

dan18 Group TitleBest ResponseYou've already chosen the best response.1
y=\[\sqrt{2x}\]
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so did u find y' ?
 one year ago

dan18 Group TitleBest ResponseYou've already chosen the best response.1
y=4[\sqrt{2x}\]
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
could u differentiate y ?
 one year ago

miteshchvm Group TitleBest ResponseYou've already chosen the best response.0
differentiate the function, then put the differentiated equation = 0 you will have either one answer or 2, if you get two answers, the one which has negative value will be the maximum value of the function ;)
 one year ago

dan18 Group TitleBest ResponseYou've already chosen the best response.1
is it the y value?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
have u learned to differentiate x^n ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so couldn't u differentiate y=4 sqrt(2x) ??
 one year ago

dan18 Group TitleBest ResponseYou've already chosen the best response.1
does the max. value asked here is the x or the y value?
 one year ago

dan18 Group TitleBest ResponseYou've already chosen the best response.1
y'= 2/(2x)^(1/2)
 one year ago

akash_809 Group TitleBest ResponseYou've already chosen the best response.0
@dan18 , the correct way is to differentiate and equate to zero , but just by looking at this question once can tell it's maximum value is infinity for x=infinity....pretty weird question i guess...are u sure u hv typed the question correctly
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
wouldn't it be y'= 2/((2x)^(1/2))
 one year ago

dan18 Group TitleBest ResponseYou've already chosen the best response.1
I get x=2 @ y', then subts. it to the eq. does the max. value = 0?
 one year ago

akash_809 Group TitleBest ResponseYou've already chosen the best response.0
@dan18 is the question correct ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
but actual answer is infact Max. value = 0 when x=2 http://www.wolframalpha.com/input/?i=y%3D4+sqrt%282x%29
 one year ago

dan18 Group TitleBest ResponseYou've already chosen the best response.1
\[y=4\sqrt{2x}\]
 one year ago

dan18 Group TitleBest ResponseYou've already chosen the best response.1
thak you guys!
 one year ago

akash_809 Group TitleBest ResponseYou've already chosen the best response.0
now u hv got the correct question, yes the max would be zero
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.