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hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1can be found by taking the derivative of that funtion and equating it to 0.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1could u differentiate y ?

miteshchvm
 2 years ago
Best ResponseYou've already chosen the best response.0differentiate the function, then put the differentiated equation = 0 you will have either one answer or 2, if you get two answers, the one which has negative value will be the maximum value of the function ;)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1have u learned to differentiate x^n ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1so couldn't u differentiate y=4 sqrt(2x) ??

dan18
 2 years ago
Best ResponseYou've already chosen the best response.1does the max. value asked here is the x or the y value?

akash_809
 2 years ago
Best ResponseYou've already chosen the best response.0@dan18 , the correct way is to differentiate and equate to zero , but just by looking at this question once can tell it's maximum value is infinity for x=infinity....pretty weird question i guess...are u sure u hv typed the question correctly

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1wouldn't it be y'= 2/((2x)^(1/2))

dan18
 2 years ago
Best ResponseYou've already chosen the best response.1I get x=2 @ y', then subts. it to the eq. does the max. value = 0?

akash_809
 2 years ago
Best ResponseYou've already chosen the best response.0@dan18 is the question correct ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1but actual answer is infact Max. value = 0 when x=2 http://www.wolframalpha.com/input/?i=y%3D4+sqrt%282x%29

akash_809
 2 years ago
Best ResponseYou've already chosen the best response.0now u hv got the correct question, yes the max would be zero
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