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hartnn Group TitleBest ResponseYou've already chosen the best response.1
can be found by taking the derivative of that funtion and equating it to 0.
 2 years ago

dan18 Group TitleBest ResponseYou've already chosen the best response.1
y=\[\sqrt{2x}\]
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so did u find y' ?
 2 years ago

dan18 Group TitleBest ResponseYou've already chosen the best response.1
y=4[\sqrt{2x}\]
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
could u differentiate y ?
 2 years ago

miteshchvm Group TitleBest ResponseYou've already chosen the best response.0
differentiate the function, then put the differentiated equation = 0 you will have either one answer or 2, if you get two answers, the one which has negative value will be the maximum value of the function ;)
 2 years ago

dan18 Group TitleBest ResponseYou've already chosen the best response.1
is it the y value?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
have u learned to differentiate x^n ?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so couldn't u differentiate y=4 sqrt(2x) ??
 2 years ago

dan18 Group TitleBest ResponseYou've already chosen the best response.1
does the max. value asked here is the x or the y value?
 2 years ago

dan18 Group TitleBest ResponseYou've already chosen the best response.1
y'= 2/(2x)^(1/2)
 2 years ago

akash_809 Group TitleBest ResponseYou've already chosen the best response.0
@dan18 , the correct way is to differentiate and equate to zero , but just by looking at this question once can tell it's maximum value is infinity for x=infinity....pretty weird question i guess...are u sure u hv typed the question correctly
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
wouldn't it be y'= 2/((2x)^(1/2))
 2 years ago

dan18 Group TitleBest ResponseYou've already chosen the best response.1
I get x=2 @ y', then subts. it to the eq. does the max. value = 0?
 2 years ago

akash_809 Group TitleBest ResponseYou've already chosen the best response.0
@dan18 is the question correct ?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
but actual answer is infact Max. value = 0 when x=2 http://www.wolframalpha.com/input/?i=y%3D4+sqrt%282x%29
 2 years ago

dan18 Group TitleBest ResponseYou've already chosen the best response.1
\[y=4\sqrt{2x}\]
 2 years ago

dan18 Group TitleBest ResponseYou've already chosen the best response.1
thak you guys!
 2 years ago

akash_809 Group TitleBest ResponseYou've already chosen the best response.0
now u hv got the correct question, yes the max would be zero
 2 years ago
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