The maximum value of the function

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The maximum value of the function

Mathematics
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can be found by taking the derivative of that funtion and equating it to 0.
y=\[\sqrt{2-x}\]
so did u find y' ?

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Other answers:

y=-4[\sqrt{2-x}\]
could u differentiate y ?
differentiate the function, then put the differentiated equation = 0 you will have either one answer or 2, if you get two answers, the one which has negative value will be the maximum value of the function ;)
is it the y value?
have u learned to differentiate x^n ?
y'= nx^n-1
so couldn't u differentiate y=-4 sqrt(2-x) ??
does the max. value asked here is the x or the y value?
y value
y'= 2/(2-x)^-(1/2)
@dan18 , the correct way is to differentiate and equate to zero , but just by looking at this question once can tell it's maximum value is infinity for x=-infinity....pretty weird question i guess...are u sure u hv typed the question correctly
wouldn't it be y'= 2/((2-x)^(1/2))
I get x=2 @ y', then subts. it to the eq. does the max. value = 0?
@dan18 is the question correct ?
but actual answer is infact Max. value = 0 when x=2 http://www.wolframalpha.com/input/?i=y%3D-4+sqrt%282-x%29
\[y=-4\sqrt{2-x}\]
thak you guys!
now u hv got the correct question, yes the max would be zero

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