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frx
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A collection of books has 5 books on mathematics, 7 books on physics and 6 books on chemistry. In how many ways can you combine the collection on a shelf if you want the same subject to stand together?
The combinations within each subject should be, 5!, 7! and 6!, right? But how do i calculate the combinations so that they stand together?
 2 years ago
 2 years ago
frx Group Title
A collection of books has 5 books on mathematics, 7 books on physics and 6 books on chemistry. In how many ways can you combine the collection on a shelf if you want the same subject to stand together? The combinations within each subject should be, 5!, 7! and 6!, right? But how do i calculate the combinations so that they stand together?
 2 years ago
 2 years ago

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satellite73 Group TitleBest ResponseYou've already chosen the best response.1
there are \(3!=6\) ways to arrange the three subjects
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
so multiply all that together and then multiply by 6
 2 years ago

frx Group TitleBest ResponseYou've already chosen the best response.0
Multiply which together? 5!6!7! ?
 2 years ago

frx Group TitleBest ResponseYou've already chosen the best response.0
Who did you choose what to divide with?
 2 years ago

frx Group TitleBest ResponseYou've already chosen the best response.0
Permutations like? \[\frac{ 5!6!7! }{ (5!6!7!?) }\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
hold on
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
you are taking all the books right? don't get married to these formulas the number of ways to arrange items is 5! by the counting principle. similarly for 6 items and 7 items this is not asking you how many ways you can arrange 4 out of 10 for example
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
\(5!\) ways for math books, by the counting principle \(6!\) ways for the chemistry books by the counting principle and \(7!\) ways for the physics books, again by the counting principle there if you had them arranged as {math, physics, chemistry} then again by the counting principle there would be \(5!6!7!\) ways to arrange the books, but there are \(3!=6\) arrangments of the subjects, so you again need to multiply by 6 i.e. \(3!5!6!7!\)
 2 years ago

frx Group TitleBest ResponseYou've already chosen the best response.0
Oh I get it! Thank you so much! :D
 2 years ago
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