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amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0im not sure if that function expresses the equality between them, so you might need to say something regarding the roots of it; when f(x)=0

akash_809
 2 years ago
Best ResponseYou've already chosen the best response.1@amistre64 but he posted it as an equality and i think if we draw there graphs we will see there there will be n number of roots.So roots won't be meaningfull

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0im not sure one way over the other :) just a gut feeling

akash_809
 2 years ago
Best ResponseYou've already chosen the best response.1@godfreysown yes equate it to zero

godfreysown
 2 years ago
Best ResponseYou've already chosen the best response.0so why is it that this simple manipulation turns an equation into a function of x? (PS: I've attached a graph of your f(x) )

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0a relation is roughly defined as any interaction or change in output resulting from input \[g(a) = {b_1,b_2,b_3,...}\]there need not be any unique answer. This is not very useful when we are trying to make predictions about how something will react. a function is a special kind of relation and is defined as an equation that has only one output value (its unique) for any given input value. \[f(a) = b\]as such, we can use these to determine past and future, as well as present outputs from a system that can be modeled by functions

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0if 2 things are equal; then subtracting one from the other leaves us with nothing. To determine when: sin(x)=e^(x) , we can subtract one from the other and determine at what values of "x" the function equals zero. also, since e^(x) never equates to zero on its own; we can divide it out instead\[f(x)=\frac{sin(x)}{e^{x}}=e^{x}~sin(x)=1\] \[f(x)=e^{x}~sin(x)1 =0\]

akash_809
 2 years ago
Best ResponseYou've already chosen the best response.1@amistre64 haven't u complicated the equation, i would always prefer to solve f(x)=sinxe^(x) rather than f(x)e^x sinx1

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0it asked for a function; complication wasnt specified :)

akash_809
 2 years ago
Best ResponseYou've already chosen the best response.1@amistre64 he he nice one :), but tasks of using maths is to always make things simple, isn't it i guessed it that way or may be is is not

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0most maths are done on computers these days, and a computer has no concept of simple. What might relate is "number" of computations required in which you would want to streamline it to reduce the number of steps that a computer would have to take for it.

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0ive got no idea which function between ours would be "simpler" for a computer tho

akash_809
 2 years ago
Best ResponseYou've already chosen the best response.1@amistre64 agreed :) , i think you are a mod , i have mailed at abuse@openstudy.com to delete my account , can u help in this.Also i have posted in openstudy feedback

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0i dont have the abilities to alter accounts.

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0..and i dont have any pull in that area either ... thats under the operations of the administrators
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