## Shehab 3 years ago 5(x-2) greater than 4 (2x+6)+2

1. ParthKohli

What you want to do is to add $$\rm 5(x + 2)$$ and $$\rm 4(2x + 6) + 2$$.

2. sue101

5(x-2) <4(2x+6) +2

3. ParthKohli

Wait... is that the question or what? And it's $$>$$, not $$<$$. @sue

4. sue101

First you have to distribute 5 to x -2 which would be... and also distribute 4 to 5x - 10 > 8x +24 + 2

5. sue101

6. sue101

5x - 10 > 8x +24 + 2 Combine like terms. subtract 5x from both sides 5x - 10 > 8x +24 + 2 -5x -5x -------------------- -10 > 3x + 26 no you have to subtract -26 from both sides -10 > 3x + 26 -26 - 26 ---------------- -36 > 3x Now you divide 3 from both sides /3 /3 ---------- 12 > x

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