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WhyteMonks

  • 2 years ago

Anyone knows how to do this?? Separate 38 into two numbers such that three times the smaller is 16 less than twice the larger.

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  1. hartnn
    • 2 years ago
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    yup.

  2. hartnn
    • 2 years ago
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    let 38 be separated into x and 38-x

  3. WhyteMonks
    • 2 years ago
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    okay

  4. WhyteMonks
    • 2 years ago
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    do we set them equal to each other?

  5. hartnn
    • 2 years ago
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    three times the smaller is 16 less than twice the larger. so 3x+16 2(36-x) got this ?

  6. theEric
    • 2 years ago
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    Only if those two "numbers" are equal to each other! Otherwise, no!

  7. hartnn
    • 2 years ago
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    3x+16= 2(36-x)

  8. WhyteMonks
    • 2 years ago
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    okay, then solve right?

  9. hartnn
    • 2 years ago
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    yup

  10. hartnn
    • 2 years ago
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    find x from there, u will get the smaller number

  11. WhyteMonks
    • 2 years ago
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    then substitute for the right, correct?

  12. WhyteMonks
    • 2 years ago
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    larger*

  13. hartnn
    • 2 years ago
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    yes, but first tell me what did u get 'x' value.

  14. WhyteMonks
    • 2 years ago
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    11.2

  15. WhyteMonks
    • 2 years ago
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    is that correct?

  16. hartnn
    • 2 years ago
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    yes, even i get 11.2, i wonder why is it not and integer, anyways, find larger using 36-x= ?

  17. WhyteMonks
    • 2 years ago
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    using 36? or 38?

  18. hartnn
    • 2 years ago
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    sorry 38

  19. WhyteMonks
    • 2 years ago
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    its okay, but I got 26.8 for large

  20. hartnn
    • 2 years ago
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    ohh.thats why we didn't get an integer, its 38, sorry my typing mistake

  21. WhyteMonks
    • 2 years ago
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    oh

  22. hartnn
    • 2 years ago
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    solve this : 3x+16= 2(38-x)

  23. WhyteMonks
    • 2 years ago
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    okay

  24. WhyteMonks
    • 2 years ago
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    i got 28 for large, 10 for small

  25. hartnn
    • 2 years ago
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    i got x=12, please verify the calculations.....

  26. WhyteMonks
    • 2 years ago
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    oh yeah, your're right

  27. WhyteMonks
    • 2 years ago
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    the larger is 26

  28. hartnn
    • 2 years ago
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    thats correct :)

  29. WhyteMonks
    • 2 years ago
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    thank you

  30. hartnn
    • 2 years ago
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    welcome ^_^

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