WhyteMonks
Anyone knows how to do this?? Separate 38 into two numbers such that three times the smaller is 16 less than twice the larger.



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hartnn
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yup.

hartnn
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let 38 be separated into x and 38x

WhyteMonks
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okay

WhyteMonks
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do we set them equal to each other?

hartnn
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three times the smaller is 16 less than twice the larger.
so
3x+16 2(36x)
got this ?

theEric
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Only if those two "numbers" are equal to each other! Otherwise, no!

hartnn
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3x+16= 2(36x)

WhyteMonks
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okay, then solve right?

hartnn
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yup

hartnn
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find x from there, u will get the smaller number

WhyteMonks
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then substitute for the right, correct?

WhyteMonks
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larger*

hartnn
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yes, but first tell me what did u get 'x' value.

WhyteMonks
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11.2

WhyteMonks
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is that correct?

hartnn
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yes, even i get 11.2, i wonder why is it not and integer,
anyways, find larger using 36x= ?

WhyteMonks
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using 36? or 38?

hartnn
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sorry 38

WhyteMonks
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its okay, but I got 26.8 for large

hartnn
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ohh.thats why we didn't get an integer, its 38,
sorry my typing mistake

WhyteMonks
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oh

hartnn
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solve this :
3x+16= 2(38x)

WhyteMonks
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okay

WhyteMonks
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i got 28 for large, 10 for small

hartnn
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i got x=12, please verify the calculations.....

WhyteMonks
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oh yeah, your're right

WhyteMonks
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the larger is 26

hartnn
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thats correct :)

WhyteMonks
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thank you

hartnn
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welcome ^_^