anonymous
  • anonymous
Anyone knows how to do this?? Separate 38 into two numbers such that three times the smaller is 16 less than twice the larger.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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hartnn
  • hartnn
yup.
hartnn
  • hartnn
let 38 be separated into x and 38-x
anonymous
  • anonymous
okay

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More answers

anonymous
  • anonymous
do we set them equal to each other?
hartnn
  • hartnn
three times the smaller is 16 less than twice the larger. so 3x+16 2(36-x) got this ?
theEric
  • theEric
Only if those two "numbers" are equal to each other! Otherwise, no!
hartnn
  • hartnn
3x+16= 2(36-x)
anonymous
  • anonymous
okay, then solve right?
hartnn
  • hartnn
yup
hartnn
  • hartnn
find x from there, u will get the smaller number
anonymous
  • anonymous
then substitute for the right, correct?
anonymous
  • anonymous
larger*
hartnn
  • hartnn
yes, but first tell me what did u get 'x' value.
anonymous
  • anonymous
11.2
anonymous
  • anonymous
is that correct?
hartnn
  • hartnn
yes, even i get 11.2, i wonder why is it not and integer, anyways, find larger using 36-x= ?
anonymous
  • anonymous
using 36? or 38?
hartnn
  • hartnn
sorry 38
anonymous
  • anonymous
its okay, but I got 26.8 for large
hartnn
  • hartnn
ohh.thats why we didn't get an integer, its 38, sorry my typing mistake
anonymous
  • anonymous
oh
hartnn
  • hartnn
solve this : 3x+16= 2(38-x)
anonymous
  • anonymous
okay
anonymous
  • anonymous
i got 28 for large, 10 for small
hartnn
  • hartnn
i got x=12, please verify the calculations.....
anonymous
  • anonymous
oh yeah, your're right
anonymous
  • anonymous
the larger is 26
hartnn
  • hartnn
thats correct :)
anonymous
  • anonymous
thank you
hartnn
  • hartnn
welcome ^_^

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