## WhyteMonks 3 years ago Anyone knows how to do this?? Separate 38 into two numbers such that three times the smaller is 16 less than twice the larger.

1. hartnn

yup.

2. hartnn

let 38 be separated into x and 38-x

3. WhyteMonks

okay

4. WhyteMonks

do we set them equal to each other?

5. hartnn

three times the smaller is 16 less than twice the larger. so 3x+16 2(36-x) got this ?

6. theEric

Only if those two "numbers" are equal to each other! Otherwise, no!

7. hartnn

3x+16= 2(36-x)

8. WhyteMonks

okay, then solve right?

9. hartnn

yup

10. hartnn

find x from there, u will get the smaller number

11. WhyteMonks

then substitute for the right, correct?

12. WhyteMonks

larger*

13. hartnn

yes, but first tell me what did u get 'x' value.

14. WhyteMonks

11.2

15. WhyteMonks

is that correct?

16. hartnn

yes, even i get 11.2, i wonder why is it not and integer, anyways, find larger using 36-x= ?

17. WhyteMonks

using 36? or 38?

18. hartnn

sorry 38

19. WhyteMonks

its okay, but I got 26.8 for large

20. hartnn

ohh.thats why we didn't get an integer, its 38, sorry my typing mistake

21. WhyteMonks

oh

22. hartnn

solve this : 3x+16= 2(38-x)

23. WhyteMonks

okay

24. WhyteMonks

i got 28 for large, 10 for small

25. hartnn

i got x=12, please verify the calculations.....

26. WhyteMonks

oh yeah, your're right

27. WhyteMonks

the larger is 26

28. hartnn

thats correct :)

29. WhyteMonks

thank you

30. hartnn

welcome ^_^