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TomLikesPhysics
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lim_{x rightarrow infty} (3x+sqrt{9x^2+4x5})
The answer is apparently 2/3. But I can´t loose the squareroot term at any place so I always end up with infinity  infinity = 0.
How do I do this limit right?
 2 years ago
 2 years ago
TomLikesPhysics Group Title
lim_{x rightarrow infty} (3x+sqrt{9x^2+4x5}) The answer is apparently 2/3. But I can´t loose the squareroot term at any place so I always end up with infinity  infinity = 0. How do I do this limit right?
 2 years ago
 2 years ago

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TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.0
\[\lim_{x \rightarrow \infty} (3x+\sqrt{9x^2+4x5})\]
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.0
That is limit I am talking about.
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
rationalize it.. see if it it helps..which it should..
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
getting me ??
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.0
I guess... let me show your where I stuck right now.
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
you're right till there.. now,, take x^2 common from the sqrt and in all,, x common from the denominator,, you see the solution now ?
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.0
I can not quite follow you here.
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
you have (4x)/(sqrt(9x^2 +4x 5) + 3x) = (4x)( x sqrt( 9 + 4/x  5/x^2 ) + 3x following till here ?
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.0
yup
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
now,,x gets cancelled from numerator and denominator .. is much easier then right ?
 2 years ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.0
Ah... now I understand. Thanks a lot shubhamsrg. I never thought of doing that one. :) thx
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
nevermind,,glad to help ! :)
 2 years ago
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