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TomLikesPhysics
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lim_{x rightarrow infty} (3x+sqrt{9x^2+4x5})
The answer is apparently 2/3. But I can´t loose the squareroot term at any place so I always end up with infinity  infinity = 0.
How do I do this limit right?
 one year ago
 one year ago
TomLikesPhysics Group Title
lim_{x rightarrow infty} (3x+sqrt{9x^2+4x5}) The answer is apparently 2/3. But I can´t loose the squareroot term at any place so I always end up with infinity  infinity = 0. How do I do this limit right?
 one year ago
 one year ago

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TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.0
\[\lim_{x \rightarrow \infty} (3x+\sqrt{9x^2+4x5})\]
 one year ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.0
That is limit I am talking about.
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
rationalize it.. see if it it helps..which it should..
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
getting me ??
 one year ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.0
I guess... let me show your where I stuck right now.
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
you're right till there.. now,, take x^2 common from the sqrt and in all,, x common from the denominator,, you see the solution now ?
 one year ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.0
I can not quite follow you here.
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
you have (4x)/(sqrt(9x^2 +4x 5) + 3x) = (4x)( x sqrt( 9 + 4/x  5/x^2 ) + 3x following till here ?
 one year ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.0
yup
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
now,,x gets cancelled from numerator and denominator .. is much easier then right ?
 one year ago

TomLikesPhysics Group TitleBest ResponseYou've already chosen the best response.0
Ah... now I understand. Thanks a lot shubhamsrg. I never thought of doing that one. :) thx
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
nevermind,,glad to help ! :)
 one year ago
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