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anonymous
 3 years ago
The sum of minterms of a boolean function of n variables is equal to 1.
(a) Prove the above statement for n=3.
(b) Suggest a procedure for a general proof.
anonymous
 3 years ago
The sum of minterms of a boolean function of n variables is equal to 1. (a) Prove the above statement for n=3. (b) Suggest a procedure for a general proof.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0a'b'c'+a'b'c+a'bc'+a'bc+ab'c'+ab'c+abc'+abcdw:1349346391795:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0here n=3 .. so we have 8 minterms ..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0According to KMap law, the result of grouping of 8 1's or 0's [1's for SOP and 0's for POS ] is 1.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Another way of doing it can be: acronyms= (1X) = X bar as i can not write it directly As you know A+(1A) =1 So abc+(1abc)=1 similarly other pairs can be solve and we will get 1+1+1+1 which itself is equal to 1. Hence proved.
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