Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
so than (m+10)(m+1)=0 ok ?
 one year ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
@jhonyy9 it would just be \[(m+10)(m+1)\] its not a quadratic equation.
 one year ago

yoyoyoyo123 Group TitleBest ResponseYou've already chosen the best response.0
its quadratic factorization :/ i understand it i just need help with how to work out the second part as in the + or  ...... if anyone can help me i would be most obliged
 one year ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
the part that looks like this: \[x=\frac{b\pm\sqrt{b^{2}4ac}}{2a}\]
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
so always when you need to factoriz a quadratic equation so you need getting two numbers with sum equal ,,b" and product equal c when you know that b and c are from the form of the base of quadratic equation what is ax^2 +bx +c =0 hope so much that is understandably sure right
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
so here in this case will be 10 and 1 because 10 +1 =11 ane 10*1 =10
 one year ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
\[m^2+11m+10\] thats what it is. jut with out the 0.
 one year ago

yoyoyoyo123 Group TitleBest ResponseYou've already chosen the best response.0
thank you :)
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.