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yoyoyoyo123

  • 2 years ago

m^2+11m+10

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  1. jhonyy9
    • 2 years ago
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    so than (m+10)(m+1)=0 ok ?

  2. andriod09
    • 2 years ago
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    @jhonyy9 it would just be \[(m+10)(m+1)\] its not a quadratic equation.

  3. yoyoyoyo123
    • 2 years ago
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    its quadratic factorization :/ i understand it i just need help with how to work out the second part as in the + or - ...... if anyone can help me i would be most obliged

  4. andriod09
    • 2 years ago
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    the part that looks like this: \[x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}\]

  5. jhonyy9
    • 2 years ago
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    so always when you need to factoriz a quadratic equation so you need getting two numbers with sum equal ,,b" and product equal c when you know that b and c are from the form of the base of quadratic equation what is ax^2 +bx +c =0 hope so much that is understandably sure right

  6. jhonyy9
    • 2 years ago
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    so here in this case will be 10 and 1 because 10 +1 =11 ane 10*1 =10

  7. jhonyy9
    • 2 years ago
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    ok ?

  8. andriod09
    • 2 years ago
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    \[m^2+11m+10\] thats what it is. jut with out the 0.

  9. yoyoyoyo123
    • 2 years ago
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    thank you :)

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