Here's the question you clicked on:
yoyoyoyo123
m^2+11m+10
so than (m+10)(m+1)=0 ok ?
@jhonyy9 it would just be \[(m+10)(m+1)\] its not a quadratic equation.
its quadratic factorization :/ i understand it i just need help with how to work out the second part as in the + or - ...... if anyone can help me i would be most obliged
the part that looks like this: \[x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}\]
so always when you need to factoriz a quadratic equation so you need getting two numbers with sum equal ,,b" and product equal c when you know that b and c are from the form of the base of quadratic equation what is ax^2 +bx +c =0 hope so much that is understandably sure right
so here in this case will be 10 and 1 because 10 +1 =11 ane 10*1 =10
\[m^2+11m+10\] thats what it is. jut with out the 0.