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anonymous
 4 years ago
how do you find the midpoint with two ordered pairs,
(12,11), (5,13)
anonymous
 4 years ago
how do you find the midpoint with two ordered pairs, (12,11), (5,13)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Just think, first, about what a middle point between an x value of 12 and an x value of 5 might be. Don't worry about the y for now... what is the x value of the middle point between those two x values?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(12 + 5)/2, yes... I think that's what you meant. Can you find the mid point between the y values?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so for x its 8.5 and for y its 1 right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Looks good to me... always smart to think about where that mid point would actually be in relation to the two endpoints... if you accidentally made a math mistake, your midpoint would be somewhere not between the other 2 points. a quick sketch should tell you if it seems right.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can i ask you another question?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[(1,1), (1+3\sqrt{3}, 4)\) how do i combine the 1 and the 3\[\sqrt{3}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sry how to i combine the square root?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you add: 1 + (1 + 3sqrt(3) ) = 1  1 + 3sqrt(3) = 2 + 3sqrt(3) then divide the whole thing by 2: (2 + 3sqrt(3) ) / 2 leaving you: 2/2 + (3/2)sqrt(3)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you don't combine the square root... For example, it's sort of like saying "how do I divide x + 2 by 2?" You don't combine the x and the 2... they are already combined by the + symbol... you just set it up as (x+2)/2 and if you want, you can simplify to (x/2) + (2/2) = (x/2) + 1
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