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dddan
Group Title
how do you find the midpoint with two ordered pairs,
(12,11), (5,13)
 one year ago
 one year ago
dddan Group Title
how do you find the midpoint with two ordered pairs, (12,11), (5,13)
 one year ago
 one year ago

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JakeV8 Group TitleBest ResponseYou've already chosen the best response.1
Just think, first, about what a middle point between an x value of 12 and an x value of 5 might be. Don't worry about the y for now... what is the x value of the middle point between those two x values?
 one year ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
so its 12+5/2?....
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.1
(12 + 5)/2, yes... I think that's what you meant. Can you find the mid point between the y values?
 one year ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
so for x its 8.5 and for y its 1 right?
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.1
Looks good to me... always smart to think about where that mid point would actually be in relation to the two endpoints... if you accidentally made a math mistake, your midpoint would be somewhere not between the other 2 points. a quick sketch should tell you if it seems right.
 one year ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
can i ask you another question?
 one year ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
\[(1,1), (1+3\sqrt{3}, 4)\) how do i combine the 1 and the 3\[\sqrt{3}\]
 one year ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
sry how to i combine the square root?
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.1
you add: 1 + (1 + 3sqrt(3) ) = 1  1 + 3sqrt(3) = 2 + 3sqrt(3) then divide the whole thing by 2: (2 + 3sqrt(3) ) / 2 leaving you: 2/2 + (3/2)sqrt(3)
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.1
you don't combine the square root... For example, it's sort of like saying "how do I divide x + 2 by 2?" You don't combine the x and the 2... they are already combined by the + symbol... you just set it up as (x+2)/2 and if you want, you can simplify to (x/2) + (2/2) = (x/2) + 1
 one year ago
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