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dddan Group Title

how do you find the center for a circle with the equation x^2+y^2=5x+6y

  • one year ago
  • one year ago

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  1. RadEn Group Title
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    general form equation of circle is : x^2+y^2+Ax+By+c=0 with the center is C(a,b) : a=-1/2*A, b=-1/2*B

    • one year ago
  2. dddan Group Title
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    is the center -5,6? can you explain the last part?

    • one year ago
  3. RadEn Group Title
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    ok, given equation of circle : x^2+y^2=5x+6y or x^2+y^2-5x-6y=0 so, A=-5 and B=-6 to get its center, use formula like i said before a = -1/2*A = -1/2 * (-5) = ....? b = -1/2*B = -1/2 * (-6) = ....?

    • one year ago
  4. dddan Group Title
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    alright so is it a=2.5 and b= 3 ?

    • one year ago
  5. RadEn Group Title
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    thats right

    • one year ago
  6. dddan Group Title
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    so the radius is 0? how would you draw this?

    • one year ago
  7. RadEn Group Title
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    to get its radius, u can use formula : |dw:1359839959123:dw|

    • one year ago
  8. RadEn Group Title
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    A=-5, B=-6, C=0 put of them to that formula...

    • one year ago
  9. dddan Group Title
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    ok thanks

    • one year ago
  10. RadEn Group Title
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    yw

    • one year ago
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