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dddan

  • 3 years ago

how do you find the center for a circle with the equation x^2+y^2=5x+6y

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  1. RadEn
    • 3 years ago
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    general form equation of circle is : x^2+y^2+Ax+By+c=0 with the center is C(a,b) : a=-1/2*A, b=-1/2*B

  2. dddan
    • 3 years ago
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    is the center -5,6? can you explain the last part?

  3. RadEn
    • 3 years ago
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    ok, given equation of circle : x^2+y^2=5x+6y or x^2+y^2-5x-6y=0 so, A=-5 and B=-6 to get its center, use formula like i said before a = -1/2*A = -1/2 * (-5) = ....? b = -1/2*B = -1/2 * (-6) = ....?

  4. dddan
    • 3 years ago
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    alright so is it a=2.5 and b= 3 ?

  5. RadEn
    • 3 years ago
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    thats right

  6. dddan
    • 3 years ago
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    so the radius is 0? how would you draw this?

  7. RadEn
    • 3 years ago
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    to get its radius, u can use formula : |dw:1359839959123:dw|

  8. RadEn
    • 3 years ago
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    A=-5, B=-6, C=0 put of them to that formula...

  9. dddan
    • 3 years ago
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    ok thanks

  10. RadEn
    • 3 years ago
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    yw

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