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 2 years ago
Statistics
I'm trying to create a Frequency Table.
Please let me know if I'm doing it right.
One minute please...
 2 years ago
Statistics I'm trying to create a Frequency Table. Please let me know if I'm doing it right. One minute please...

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MathSofiya
 2 years ago
Best ResponseYou've already chosen the best response.0\[\quad \begin{array}{ccccc} \hline \frac{\textrm{class limits}}{\textrm{lowerupper}} & \frac{\textrm{class boundary}}{\textrm{lowerupper}} & \frac{\textrm{class}}{\textrm{midpoint}} &\text{tally}&\text{frequency}&\frac{\text{cumulative}}{\text{frequency}}\\ \hline 1 & & \\ \hline & & 4&6 \\ \hline & 5 & 4\\ \hline & & \\ \hline & 1 & \\ \hline & 1& 2\\ \hline \end{array}\] this is not the actual table. I'm new to making tables with Latex. Those numbers are just place holders so that my table doesn't collapse...now to my questions...

MathSofiya
 2 years ago
Best ResponseYou've already chosen the best response.0I found the class width to be 6 \[\frac{430}{8}=5.375\] 34 21 37 31 10 24 39 10 17 18 32 17 3 10 6 5 6 6 13 22 25 3 5 2 9 3 0 4 29 26 5 5 24 15 3 8 16 9 10 3 12 10 10 10 11 12 13 1 9 43 13 14 32 24 15

MathSofiya
 2 years ago
Best ResponseYou've already chosen the best response.0for the first column... so would I write 06 612 1224 how do I know where to start the class limits? I know that I should add six to the upper and lower limit to get to the next limits, but where do i start?

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.1Well, one thing is you don't want the classes to overlap, so maybe 06, 713, 1420, etc.

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.1It looks like discrete data, so you don't have to worry about continuity corrections.

MathSofiya
 2 years ago
Best ResponseYou've already chosen the best response.0but I have to add 6 to the lower limit and to the upper limit. If I do what you did that would be adding 7 to each 06 713 Would that mean it doesn't matter where I start? could I do... 05 611 1217 ?

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.1Yeah, I think since 0 is included in the data, 05, 611, .. would be better if you want to have 8 classes. It'll overshoot a little at the end, but will include all the data.

MathSofiya
 2 years ago
Best ResponseYou've already chosen the best response.0Why would it overshoot at the end?

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.18 classes with a width of 6 each would go to 47 (481 because starting count at 0)

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.1It's fine though, otherwise if you only had a width of 5, it would only go to 39 and that is less than your maximum value.

MathSofiya
 2 years ago
Best ResponseYou've already chosen the best response.0will do. Thanks for your help!

MathSofiya
 2 years ago
Best ResponseYou've already chosen the best response.0\[\quad \begin{array}{cccc} \hline \frac{\textrm{class limits}}{\textrm{lowerupper}} & \frac{\textrm{class boundary}}{\textrm{lowerupper}} & \frac{\textrm{class}}{\textrm{midpoint}} &\text{frequency}&\frac{\text{cumulative}}{\text{frequency}}&\frac{f}{n}\\ \hline 05 & 0.05.5 &13 &13& 2.75&0.218\\ \hline 611& 5.511.5& 15&28& 8.5 &0.27\\ \hline 1217&11.517.5& 11&39& 14.5 &0.2\\ \hline 1823&17.523.5& 3 &42& 20.5 &0.054 \\ \hline 2429&23.529.5& 6 &48& 26.5 &0.109\\ \hline 3035&29.535.5& 4 &52& 32.5 &0.072\\ \hline 3641&35.541.5& 2 &54& 38.5 &0.036\\ \hline 4247&41.547.5& 1 &55& 44.5 &0.018\\ \hline \end{array}\]
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