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alfers101

  • 3 years ago

a man whose height is 1.8m is walking directly away from a lamp fast at contrite of 1.2m/s. if the lamp s 12m above the ground, find the rate of which shadow is lengthening

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  1. alfers101
    • 3 years ago
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    this is about time rates on differential calculus

  2. completeidiot
    • 3 years ago
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    have you tried drawing a picture yet

  3. alfers101
    • 3 years ago
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    not yet :(

  4. completeidiot
    • 3 years ago
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    draw a picture, then figure out the equation where input is distance away from the lamp and out put is length of the shadow

  5. completeidiot
    • 3 years ago
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    |dw:1349318841236:dw|

  6. completeidiot
    • 3 years ago
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    then find the derivative in respect to t

  7. completeidiot
    • 3 years ago
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    dx/dt would be velocity which would be 1.2 and ds/dt would be rate the shadow increases over time

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