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amber15
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Simplify the trigonometric expression. 1/1+ sin theta + 1/1sin theta A, 2 cos^2 theta B. 2 sec^2 theta C. 2 csc^2 theta D. 2 cot^2 theta A,2 cos^2 theta B. 2 sec ^2 theta C. 2 csc^2 theta D, 2 cot^2 theta my answer is B can some one tell me if im correct i know C and A are not correct answers
 one year ago
 one year ago
amber15 Group Title
Simplify the trigonometric expression. 1/1+ sin theta + 1/1sin theta A, 2 cos^2 theta B. 2 sec^2 theta C. 2 csc^2 theta D. 2 cot^2 theta A,2 cos^2 theta B. 2 sec ^2 theta C. 2 csc^2 theta D, 2 cot^2 theta my answer is B can some one tell me if im correct i know C and A are not correct answers
 one year ago
 one year ago

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calculusfunctions Group TitleBest ResponseYou've already chosen the best response.4
\[\frac{ 1 }{ 1+\sin \theta }+\frac{ 1 }{ 1\sin \theta }\] The LCD (least common multiple of the denominators) is (1 + sin θ)(1 − sin θ). Hence \[\frac{ 1 }{ 1+\sin \theta }+\frac{ 1 }{ 1\sin \theta }\] \[=\frac{ 1\sin \theta }{(1+\sin \theta)(1\sin \theta) }+\frac{ 1+\sin \theta }{ (1+\sin \theta)(1\sin \theta) }\] \[=\frac{ 1\sin \theta +1+\sin \theta }{ (1+\sin \theta)(1\sin \theta) }\] \[=\frac{ 2 }{ 1\sin ^{2}\theta }\] \[=\frac{ 2 }{ \cos ^{2}\theta }\] \[=2\sec ^{2}\theta \] I hope that helps!
 one year ago

amber15 Group TitleBest ResponseYou've already chosen the best response.2
so the answer is D
 one year ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.4
You mean B, don't you?
 one year ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.4
Good! Don't I get a medal? lol
 one year ago

amber15 Group TitleBest ResponseYou've already chosen the best response.2
yes you get a medal and thank you
 one year ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.4
Haha! I was just trying to be funny but thank you!
 one year ago

amber15 Group TitleBest ResponseYou've already chosen the best response.2
you did good on explaining tho
 one year ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.4
Thank you!
 one year ago

rosedewittbukater Group TitleBest ResponseYou've already chosen the best response.0
@amber15 do you remember if this answer was correct?
 one year ago

amber15 Group TitleBest ResponseYou've already chosen the best response.2
yes it is correct
 one year ago

rosedewittbukater Group TitleBest ResponseYou've already chosen the best response.0
Thank you so much!
 one year ago

amber15 Group TitleBest ResponseYou've already chosen the best response.2
your welcome
 one year ago
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