amber15
  • amber15
Simplify the trigonometric expression. 1/1+ sin theta + 1/1-sin theta A, 2 cos^2 theta B. 2 sec^2 theta C. 2 csc^2 theta D. 2 cot^2 theta A,2 cos^2 theta B. 2 sec ^2 theta C. 2 csc^2 theta D, 2 cot^2 theta my answer is B can some one tell me if im correct i know C and A are not correct answers
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
calculusfunctions
  • calculusfunctions
\[\frac{ 1 }{ 1+\sin \theta }+\frac{ 1 }{ 1-\sin \theta }\] The LCD (least common multiple of the denominators) is (1 + sin θ)(1 − sin θ). Hence \[\frac{ 1 }{ 1+\sin \theta }+\frac{ 1 }{ 1-\sin \theta }\] \[=\frac{ 1-\sin \theta }{(1+\sin \theta)(1-\sin \theta) }+\frac{ 1+\sin \theta }{ (1+\sin \theta)(1-\sin \theta) }\] \[=\frac{ 1-\sin \theta +1+\sin \theta }{ (1+\sin \theta)(1-\sin \theta) }\] \[=\frac{ 2 }{ 1-\sin ^{2}\theta }\] \[=\frac{ 2 }{ \cos ^{2}\theta }\] \[=2\sec ^{2}\theta \] I hope that helps!
amber15
  • amber15
thank you
amber15
  • amber15
so the answer is D

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calculusfunctions
  • calculusfunctions
You mean B, don't you?
amber15
  • amber15
OOPS yes
calculusfunctions
  • calculusfunctions
Good! Don't I get a medal? lol
amber15
  • amber15
yes you get a medal and thank you
calculusfunctions
  • calculusfunctions
Haha! I was just trying to be funny but thank you!
amber15
  • amber15
you did good on explaining tho
calculusfunctions
  • calculusfunctions
Thank you!
rosedewittbukater
  • rosedewittbukater
@amber15 do you remember if this answer was correct?
amber15
  • amber15
yes it is correct
rosedewittbukater
  • rosedewittbukater
Thank you so much!
amber15
  • amber15
your welcome

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