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qpHalcy0nBest ResponseYou've already chosen the best response.1
\[\sqrt{a}\sqrt{b} = \sqrt{ab}\]
 one year ago

qpHalcy0nBest ResponseYou've already chosen the best response.1
\[3\sqrt{2}\] You got it.
 one year ago

rannsanBest ResponseYou've already chosen the best response.0
I do not know which answer it is
 one year ago

qpHalcy0nBest ResponseYou've already chosen the best response.1
Oh, well look here. You see my first post?
 one year ago

qpHalcy0nBest ResponseYou've already chosen the best response.1
Here: \[\sqrt{3}\sqrt{6} = \sqrt{3 * 6}\]
 one year ago

qpHalcy0nBest ResponseYou've already chosen the best response.1
Now what do you have?
 one year ago

rannsanBest ResponseYou've already chosen the best response.0
that is my simplified answer
 one year ago

qpHalcy0nBest ResponseYou've already chosen the best response.1
No, please stop doing this. That is not what we are looking for.
 one year ago

qpHalcy0nBest ResponseYou've already chosen the best response.1
Follow me step by step. What is: \[\sqrt{6 \times 3}\]
 one year ago

rannsanBest ResponseYou've already chosen the best response.0
This is my last assignment for this term.................I do appreciate the help honestly I do.
 one year ago

qpHalcy0nBest ResponseYou've already chosen the best response.1
\[\sqrt{6 \times 3} = \sqrt{18} = \sqrt{ 3 * 3 * 2} = 3 \sqrt{2}\]
 one year ago

qpHalcy0nBest ResponseYou've already chosen the best response.1
Don't ever feel stupid. It just takes seeing it over and over to realize what's happening. It's building blocks. I was in the same place, I promise you that ;)
 one year ago

rannsanBest ResponseYou've already chosen the best response.0
well I am almost 50yrs old and never learned algebra in high school
 one year ago

rannsanBest ResponseYou've already chosen the best response.0
so did I get it right?
 one year ago

rannsanBest ResponseYou've already chosen the best response.0
I have a 4.0gpa but now this term because of Algebra
 one year ago

qpHalcy0nBest ResponseYou've already chosen the best response.1
Yes, but sqrt(18) simplifies though. What I do is called a "prime factorization".
 one year ago

rannsanBest ResponseYou've already chosen the best response.0
I cannot thank you enough!
 one year ago

rannsanBest ResponseYou've already chosen the best response.0
I have more.................problems to solve
 one year ago

qpHalcy0nBest ResponseYou've already chosen the best response.1
dw:1349330370601:dw
 one year ago

qpHalcy0nBest ResponseYou've already chosen the best response.1
Since you're multiplying 3 by itself under a SQUARE root....then the 3 can just come out. Leaving the 2 by itself. So you have: \[3\sqrt{2}\]
 one year ago

rannsanBest ResponseYou've already chosen the best response.0
I got it!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! my light bulb just clicked on...
 one year ago

rannsanBest ResponseYou've already chosen the best response.0
ok I am gonna close this one out so I can post another.
 one year ago
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