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qpHalcy0n
 2 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt{a}\sqrt{b} = \sqrt{ab}\]

qpHalcy0n
 2 years ago
Best ResponseYou've already chosen the best response.1\[3\sqrt{2}\] You got it.

rannsan
 2 years ago
Best ResponseYou've already chosen the best response.0I do not know which answer it is

qpHalcy0n
 2 years ago
Best ResponseYou've already chosen the best response.1Oh, well look here. You see my first post?

qpHalcy0n
 2 years ago
Best ResponseYou've already chosen the best response.1Here: \[\sqrt{3}\sqrt{6} = \sqrt{3 * 6}\]

qpHalcy0n
 2 years ago
Best ResponseYou've already chosen the best response.1Now what do you have?

rannsan
 2 years ago
Best ResponseYou've already chosen the best response.0that is my simplified answer

qpHalcy0n
 2 years ago
Best ResponseYou've already chosen the best response.1No, please stop doing this. That is not what we are looking for.

qpHalcy0n
 2 years ago
Best ResponseYou've already chosen the best response.1Follow me step by step. What is: \[\sqrt{6 \times 3}\]

rannsan
 2 years ago
Best ResponseYou've already chosen the best response.0This is my last assignment for this term.................I do appreciate the help honestly I do.

qpHalcy0n
 2 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt{6 \times 3} = \sqrt{18} = \sqrt{ 3 * 3 * 2} = 3 \sqrt{2}\]

qpHalcy0n
 2 years ago
Best ResponseYou've already chosen the best response.1Don't ever feel stupid. It just takes seeing it over and over to realize what's happening. It's building blocks. I was in the same place, I promise you that ;)

rannsan
 2 years ago
Best ResponseYou've already chosen the best response.0well I am almost 50yrs old and never learned algebra in high school

rannsan
 2 years ago
Best ResponseYou've already chosen the best response.0I have a 4.0gpa but now this term because of Algebra

qpHalcy0n
 2 years ago
Best ResponseYou've already chosen the best response.1Yes, but sqrt(18) simplifies though. What I do is called a "prime factorization".

rannsan
 2 years ago
Best ResponseYou've already chosen the best response.0I cannot thank you enough!

rannsan
 2 years ago
Best ResponseYou've already chosen the best response.0I have more.................problems to solve

qpHalcy0n
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1349330370601:dw

qpHalcy0n
 2 years ago
Best ResponseYou've already chosen the best response.1Since you're multiplying 3 by itself under a SQUARE root....then the 3 can just come out. Leaving the 2 by itself. So you have: \[3\sqrt{2}\]

rannsan
 2 years ago
Best ResponseYou've already chosen the best response.0I got it!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! my light bulb just clicked on...

rannsan
 2 years ago
Best ResponseYou've already chosen the best response.0ok I am gonna close this one out so I can post another.
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