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rannsan

What is the simplified product of (√3)(√6)=

  • one year ago
  • one year ago

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  1. qpHalcy0n
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    \[\sqrt{a}\sqrt{b} = \sqrt{ab}\]

    • one year ago
  2. rannsan
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    9√2 √18 3√2 3

    • one year ago
  3. qpHalcy0n
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    \[3\sqrt{2}\] You got it.

    • one year ago
  4. rannsan
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    I do not know which answer it is

    • one year ago
  5. qpHalcy0n
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    Oh, well look here. You see my first post?

    • one year ago
  6. rannsan
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    3√2

    • one year ago
  7. qpHalcy0n
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    Here: \[\sqrt{3}\sqrt{6} = \sqrt{3 * 6}\]

    • one year ago
  8. qpHalcy0n
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    Now what do you have?

    • one year ago
  9. rannsan
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    3

    • one year ago
  10. rannsan
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    √3+ √12

    • one year ago
  11. rannsan
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    that is my simplified answer

    • one year ago
  12. SOMU.kvp
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    4.24175

    • one year ago
  13. qpHalcy0n
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    No, please stop doing this. That is not what we are looking for.

    • one year ago
  14. qpHalcy0n
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    Follow me step by step. What is: \[\sqrt{6 \times 3}\]

    • one year ago
  15. rannsan
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    This is my last assignment for this term.................I do appreciate the help honestly I do.

    • one year ago
  16. SOMU.kvp
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    what mr.qpha?

    • one year ago
  17. qpHalcy0n
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    \[\sqrt{6 \times 3} = \sqrt{18} = \sqrt{ 3 * 3 * 2} = 3 \sqrt{2}\]

    • one year ago
  18. rannsan
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    2.44 =√6

    • one year ago
  19. rannsan
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    \[\sqrt{18}\]

    • one year ago
  20. rannsan
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    I feel so stupid

    • one year ago
  21. qpHalcy0n
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    Don't ever feel stupid. It just takes seeing it over and over to realize what's happening. It's building blocks. I was in the same place, I promise you that ;)

    • one year ago
  22. rannsan
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    well I am almost 50yrs old and never learned algebra in high school

    • one year ago
  23. rannsan
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    so did I get it right?

    • one year ago
  24. rannsan
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    I have a 4.0gpa but now this term because of Algebra

    • one year ago
  25. qpHalcy0n
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    Yes, but sqrt(18) simplifies though. What I do is called a "prime factorization".

    • one year ago
  26. rannsan
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    not this term that is

    • one year ago
  27. rannsan
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    I cannot thank you enough!

    • one year ago
  28. rannsan
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    I have more.................problems to solve

    • one year ago
  29. qpHalcy0n
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    |dw:1349330370601:dw|

    • one year ago
  30. qpHalcy0n
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    Since you're multiplying 3 by itself under a SQUARE root....then the 3 can just come out. Leaving the 2 by itself. So you have: \[3\sqrt{2}\]

    • one year ago
  31. rannsan
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    I got it!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! my light bulb just clicked on...

    • one year ago
  32. rannsan
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    ok I am gonna close this one out so I can post another.

    • one year ago
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