rannsan
What is the simplified product of (√3)(√6)=
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qpHalcy0n
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\[\sqrt{a}\sqrt{b} = \sqrt{ab}\]
rannsan
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9√2
√18
3√2
3
qpHalcy0n
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\[3\sqrt{2}\]
You got it.
rannsan
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I do not know which answer it is
qpHalcy0n
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Oh, well look here. You see my first post?
rannsan
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3√2
qpHalcy0n
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Here:
\[\sqrt{3}\sqrt{6} = \sqrt{3 * 6}\]
qpHalcy0n
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Now what do you have?
rannsan
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3
rannsan
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√3+ √12
rannsan
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that is my simplified answer
SOMU.kvp
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4.24175
qpHalcy0n
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No, please stop doing this. That is not what we are looking for.
qpHalcy0n
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Follow me step by step. What is:
\[\sqrt{6 \times 3}\]
rannsan
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This is my last assignment for this term.................I do appreciate the help honestly I do.
SOMU.kvp
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what mr.qpha?
qpHalcy0n
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\[\sqrt{6 \times 3} = \sqrt{18} = \sqrt{ 3 * 3 * 2} = 3 \sqrt{2}\]
rannsan
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2.44 =√6
rannsan
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\[\sqrt{18}\]
rannsan
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I feel so stupid
qpHalcy0n
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Don't ever feel stupid. It just takes seeing it over and over to realize what's happening. It's building blocks. I was in the same place, I promise you that ;)
rannsan
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well I am almost 50yrs old and never learned algebra in high school
rannsan
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so did I get it right?
rannsan
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I have a 4.0gpa but now this term because of Algebra
qpHalcy0n
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Yes, but sqrt(18) simplifies though. What I do is called a "prime factorization".
rannsan
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not this term that is
rannsan
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I cannot thank you enough!
rannsan
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I have more.................problems to solve
qpHalcy0n
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|dw:1349330370601:dw|
qpHalcy0n
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Since you're multiplying 3 by itself under a SQUARE root....then the 3 can just come out. Leaving the 2 by itself. So you have:
\[3\sqrt{2}\]
rannsan
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I got it!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! my light bulb just clicked on...
rannsan
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ok I am gonna close this one out so I can post another.