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carl_gauss Group TitleBest ResponseYou've already chosen the best response.1
multiply with 6 and 7 than bring x to one side. voila
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ x }{ 6 }=\frac{ x }{ 7 }+5\] to better understand here is the actual problem in the correct equation
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
Move the x's to one side. Make the denominators equal. Minus the two terms, and move the denominator over to the over side and multiply 5 by the denominator (42) and then divide by the number next to x on the side where 5(42) is. and voila
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
7x/42  6x/42 = 5 x/42=5 x=5(42)
 one year ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ x }{ 6 }=\frac{ x }{ 7 }+5\] Multiply both sides by 42 (least common multiple of 6 and 7), to obtain 7x = 6x + 210 ∴ x = 210 Do you understand?
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
so step 2 would look like x/7x/6=5
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
Then you make the denominators the same
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
which would be 42,
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
yes since 6 X 7 = 42
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
this is the part i get confused at
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
would it look like x/42?
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
but in order to make the denominators equation, you need to times the numerator by the amount that the denominator needs to make 42. eg. 6 X ? = 42 (7) so times the top x by 7 which becomes 7x. and the other becomes 6x since you need to times 7 by 6 to make 42. so it would be 7x/42  6x/42 7x6x = x so it will eventually become x/42
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
ahhh ok
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
so then is x/42=5
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
and then simplify from there
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
how do i get x by itself?
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
move the 42 over to the other side by timesing both sides by 42.
 one year ago

magepker728 Group TitleBest ResponseYou've already chosen the best response.0
dw:1349349298325:dw
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
42(x/42) = 5(42) x =210
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
thank you so much.. fractions is one thing i have an issue with..
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
that's fine :)
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
i have even harder ones... like \[\frac{ x}{ 2x+2 }=\frac{ 2x }{ 4x+4 }+\frac{ 2x3 }{ x+1 }\]
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
You use the same principle: so to add two fractions, the denominators must be the same. make the denominator under 2x simplified: 4x + 4 4(x+1) and use {2x over 4(x+1)} + {4(2x3) over 4(x+1)} as a first step
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
\[{2x \over 4(x+1)} + {4(2x3) \over 4(x+1)}\]
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
and add them \[2x + 8x 12 \over 4(x+1)\]
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
do the same with the other side and use 2(x+1) as denominator
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
\[{x \over 2(x+1)} = {6x 12 \over 4(x+1)}\]
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
and cross multiply for simplification
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
2x(x+1) = (6x12) (x+1)
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
cancel the x+1 and you have 2x = 6x12
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
and that is simplified as 4x = 12 which means x = 3
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
i believe so
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
i have one more fraction if anyone is interested in helping
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ 5 }{ y4 }\frac{ 8 }{ y4 }=\frac{ 2 }{ y^216 }\]
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
it throws me off to add sqrt
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
um... you could do it like this: \[{3 \over y4} = {2 \over y^2 16}\] \[{3 \over y 4} = {2 \over (y+4)(y4)}\]
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
Then knock off the y4 so you're left with \[3 = {2 \over y+4}\]
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
and then use 3 (y+4) = 2 and simplify 3y  12 = 2 3y = 2 +12 3y = 14 y = 14/3
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
wow that was easier than i thought
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
You were only stumped by the y^2  16 which is simplified as (y4)(y+4)
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
thank you so much for helping me with these!
 one year ago

order Group TitleBest ResponseYou've already chosen the best response.1
No probelma :)
 one year ago
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