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carl_gauss Group TitleBest ResponseYou've already chosen the best response.1
multiply with 6 and 7 than bring x to one side. voila
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ x }{ 6 }=\frac{ x }{ 7 }+5\] to better understand here is the actual problem in the correct equation
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
Move the x's to one side. Make the denominators equal. Minus the two terms, and move the denominator over to the over side and multiply 5 by the denominator (42) and then divide by the number next to x on the side where 5(42) is. and voila
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
7x/42  6x/42 = 5 x/42=5 x=5(42)
 2 years ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ x }{ 6 }=\frac{ x }{ 7 }+5\] Multiply both sides by 42 (least common multiple of 6 and 7), to obtain 7x = 6x + 210 ∴ x = 210 Do you understand?
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
so step 2 would look like x/7x/6=5
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
Then you make the denominators the same
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
which would be 42,
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
yes since 6 X 7 = 42
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
this is the part i get confused at
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
would it look like x/42?
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
but in order to make the denominators equation, you need to times the numerator by the amount that the denominator needs to make 42. eg. 6 X ? = 42 (7) so times the top x by 7 which becomes 7x. and the other becomes 6x since you need to times 7 by 6 to make 42. so it would be 7x/42  6x/42 7x6x = x so it will eventually become x/42
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
ahhh ok
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
so then is x/42=5
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
and then simplify from there
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
how do i get x by itself?
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
move the 42 over to the other side by timesing both sides by 42.
 2 years ago

magepker728 Group TitleBest ResponseYou've already chosen the best response.0
dw:1349349298325:dw
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
42(x/42) = 5(42) x =210
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
thank you so much.. fractions is one thing i have an issue with..
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
that's fine :)
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
i have even harder ones... like \[\frac{ x}{ 2x+2 }=\frac{ 2x }{ 4x+4 }+\frac{ 2x3 }{ x+1 }\]
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
You use the same principle: so to add two fractions, the denominators must be the same. make the denominator under 2x simplified: 4x + 4 4(x+1) and use {2x over 4(x+1)} + {4(2x3) over 4(x+1)} as a first step
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
\[{2x \over 4(x+1)} + {4(2x3) \over 4(x+1)}\]
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
and add them \[2x + 8x 12 \over 4(x+1)\]
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
do the same with the other side and use 2(x+1) as denominator
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
\[{x \over 2(x+1)} = {6x 12 \over 4(x+1)}\]
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
and cross multiply for simplification
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
2x(x+1) = (6x12) (x+1)
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
cancel the x+1 and you have 2x = 6x12
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
and that is simplified as 4x = 12 which means x = 3
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
i believe so
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
i have one more fraction if anyone is interested in helping
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ 5 }{ y4 }\frac{ 8 }{ y4 }=\frac{ 2 }{ y^216 }\]
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
it throws me off to add sqrt
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
um... you could do it like this: \[{3 \over y4} = {2 \over y^2 16}\] \[{3 \over y 4} = {2 \over (y+4)(y4)}\]
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
Then knock off the y4 so you're left with \[3 = {2 \over y+4}\]
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
and then use 3 (y+4) = 2 and simplify 3y  12 = 2 3y = 2 +12 3y = 14 y = 14/3
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
wow that was easier than i thought
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
You were only stumped by the y^2  16 which is simplified as (y4)(y+4)
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.0
thank you so much for helping me with these!
 2 years ago

order Group TitleBest ResponseYou've already chosen the best response.1
No probelma :)
 2 years ago
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