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\[\left[\begin{matrix}3 & 13 \\ x & x-11\end{matrix}\right]\]

are they fractions or are they dividends?

there fractions being added.

sorry forgot to write that

i think it is
\[\frac{3}{x}+\frac{13}{x-11}\] but i could be wrong

in any case add fraction the same way you always do
\[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bc}\]

Thats exactly how you write it

\[\frac{3}{x}+\frac{13}{x-11}\]\[\frac{3(x-11)+13x}{x^2-11}\] would that be right @satellite73

if you multiply out in the denominator it will be \(x^2-11x\)

Im really confused can you do it step by step?

btw i made a typo above, it should be
\[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\]

in your case \(a=3,b=x,c=13,d=x-11\)

\[*\frac{3(x-11)+13x}{x(x-11)}*\]

and thats the answer?

i believe that would be the answer.