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toriebabii
 2 years ago
Best ResponseYou've already chosen the best response.0\[\left[\begin{matrix}3 & 13 \\ x & x11\end{matrix}\right]\]

andriod09
 2 years ago
Best ResponseYou've already chosen the best response.0are they fractions or are they dividends?

toriebabii
 2 years ago
Best ResponseYou've already chosen the best response.0there fractions being added.

toriebabii
 2 years ago
Best ResponseYou've already chosen the best response.0sorry forgot to write that

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0i think it is \[\frac{3}{x}+\frac{13}{x11}\] but i could be wrong

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0in any case add fraction the same way you always do \[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bc}\]

toriebabii
 2 years ago
Best ResponseYou've already chosen the best response.0Thats exactly how you write it

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0if i am right in the question, you should get \[\frac{3(x11)+13x}{x(x11)}\]which you can clean up with some algebra

andriod09
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{3}{x}+\frac{13}{x11}\]\[\frac{3(x11)+13x}{x^211}\] would that be right @satellite73

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0if you multiply out in the denominator it will be \(x^211x\)

toriebabii
 2 years ago
Best ResponseYou've already chosen the best response.0Im really confused can you do it step by step?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0btw i made a typo above, it should be \[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0@toriebabii did you see what i wrote above about adding fractions? it is the same way with variables as with numbers \[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0in your case \(a=3,b=x,c=13,d=x11\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0put them directly in to the right hand side of the method for addition \[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\] with careful use of parentheses, and you will get the answer

andriod09
 2 years ago
Best ResponseYou've already chosen the best response.0so then like mine said it would be: 3x+13x−11 \[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\]\[\frac{3}{x}\frac{13}{x11}\]\[\frac{3(x11)+13x}{x(x11)}

andriod09
 2 years ago
Best ResponseYou've already chosen the best response.0\[*\frac{3(x11)+13x}{x(x11)}*\]

toriebabii
 2 years ago
Best ResponseYou've already chosen the best response.0and thats the answer?

andriod09
 2 years ago
Best ResponseYou've already chosen the best response.0no, now you simplify. \[\frac{3(x11)+13x}{x(x11)}\]\[\frac{3x33+13x}{x^211}\]\[\frac{16x33}{x^211}\] do you see anything wlse to do in this equation?

andriod09
 2 years ago
Best ResponseYou've already chosen the best response.0i believe that would be the answer.
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