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toriebabii Group TitleBest ResponseYou've already chosen the best response.0
\[\left[\begin{matrix}3 & 13 \\ x & x11\end{matrix}\right]\]
 2 years ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
are they fractions or are they dividends?
 2 years ago

toriebabii Group TitleBest ResponseYou've already chosen the best response.0
there fractions being added.
 2 years ago

toriebabii Group TitleBest ResponseYou've already chosen the best response.0
sorry forgot to write that
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
i think it is \[\frac{3}{x}+\frac{13}{x11}\] but i could be wrong
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
in any case add fraction the same way you always do \[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bc}\]
 2 years ago

toriebabii Group TitleBest ResponseYou've already chosen the best response.0
Thats exactly how you write it
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
if i am right in the question, you should get \[\frac{3(x11)+13x}{x(x11)}\]which you can clean up with some algebra
 2 years ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{3}{x}+\frac{13}{x11}\]\[\frac{3(x11)+13x}{x^211}\] would that be right @satellite73
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
if you multiply out in the denominator it will be \(x^211x\)
 2 years ago

toriebabii Group TitleBest ResponseYou've already chosen the best response.0
Im really confused can you do it step by step?
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
btw i made a typo above, it should be \[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
@toriebabii did you see what i wrote above about adding fractions? it is the same way with variables as with numbers \[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
in your case \(a=3,b=x,c=13,d=x11\)
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
put them directly in to the right hand side of the method for addition \[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\] with careful use of parentheses, and you will get the answer
 2 years ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
so then like mine said it would be: 3x+13x−11 \[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\]\[\frac{3}{x}\frac{13}{x11}\]\[\frac{3(x11)+13x}{x(x11)}
 2 years ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
\[*\frac{3(x11)+13x}{x(x11)}*\]
 2 years ago

toriebabii Group TitleBest ResponseYou've already chosen the best response.0
and thats the answer?
 2 years ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
no, now you simplify. \[\frac{3(x11)+13x}{x(x11)}\]\[\frac{3x33+13x}{x^211}\]\[\frac{16x33}{x^211}\] do you see anything wlse to do in this equation?
 2 years ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
i believe that would be the answer.
 2 years ago
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