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toriebabii Group TitleBest ResponseYou've already chosen the best response.0
\[\left[\begin{matrix}3 & 13 \\ x & x11\end{matrix}\right]\]
 one year ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
are they fractions or are they dividends?
 one year ago

toriebabii Group TitleBest ResponseYou've already chosen the best response.0
there fractions being added.
 one year ago

toriebabii Group TitleBest ResponseYou've already chosen the best response.0
sorry forgot to write that
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
i think it is \[\frac{3}{x}+\frac{13}{x11}\] but i could be wrong
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
in any case add fraction the same way you always do \[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bc}\]
 one year ago

toriebabii Group TitleBest ResponseYou've already chosen the best response.0
Thats exactly how you write it
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
if i am right in the question, you should get \[\frac{3(x11)+13x}{x(x11)}\]which you can clean up with some algebra
 one year ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{3}{x}+\frac{13}{x11}\]\[\frac{3(x11)+13x}{x^211}\] would that be right @satellite73
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
if you multiply out in the denominator it will be \(x^211x\)
 one year ago

toriebabii Group TitleBest ResponseYou've already chosen the best response.0
Im really confused can you do it step by step?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
btw i made a typo above, it should be \[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
@toriebabii did you see what i wrote above about adding fractions? it is the same way with variables as with numbers \[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
in your case \(a=3,b=x,c=13,d=x11\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
put them directly in to the right hand side of the method for addition \[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\] with careful use of parentheses, and you will get the answer
 one year ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
so then like mine said it would be: 3x+13x−11 \[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\]\[\frac{3}{x}\frac{13}{x11}\]\[\frac{3(x11)+13x}{x(x11)}
 one year ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
\[*\frac{3(x11)+13x}{x(x11)}*\]
 one year ago

toriebabii Group TitleBest ResponseYou've already chosen the best response.0
and thats the answer?
 one year ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
no, now you simplify. \[\frac{3(x11)+13x}{x(x11)}\]\[\frac{3x33+13x}{x^211}\]\[\frac{16x33}{x^211}\] do you see anything wlse to do in this equation?
 one year ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
i believe that would be the answer.
 one year ago
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