## anonymous 3 years ago 3/x+13/x-11

1. anonymous

$\left[\begin{matrix}3 & 13 \\ x & x-11\end{matrix}\right]$

2. anonymous

3. anonymous

are they fractions or are they dividends?

4. anonymous

5. anonymous

sorry forgot to write that

6. anonymous

i think it is $\frac{3}{x}+\frac{13}{x-11}$ but i could be wrong

7. anonymous

in any case add fraction the same way you always do $\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bc}$

8. anonymous

Thats exactly how you write it

9. anonymous

if i am right in the question, you should get $\frac{3(x-11)+13x}{x(x-11)}$which you can clean up with some algebra

10. anonymous

$\frac{3}{x}+\frac{13}{x-11}$$\frac{3(x-11)+13x}{x^2-11}$ would that be right @satellite73

11. anonymous

if you multiply out in the denominator it will be $$x^2-11x$$

12. anonymous

Im really confused can you do it step by step?

13. anonymous

btw i made a typo above, it should be $\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}$

14. anonymous

@toriebabii did you see what i wrote above about adding fractions? it is the same way with variables as with numbers $\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}$

15. anonymous

in your case $$a=3,b=x,c=13,d=x-11$$

16. anonymous

put them directly in to the right hand side of the method for addition $\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}$ with careful use of parentheses, and you will get the answer

17. anonymous

so then like mine said it would be: 3x+13x−11 $\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}$$\frac{3}{x}\frac{13}{x-11}$$\frac{3(x-11)+13x}{x(x-11)} 18. anonymous \[*\frac{3(x-11)+13x}{x(x-11)}*$

19. anonymous

20. anonymous

no, now you simplify. $\frac{3(x-11)+13x}{x(x-11)}$$\frac{3x-33+13x}{x^2-11}$$\frac{16x-33}{x^2-11}$ do you see anything wlse to do in this equation?

21. anonymous

i believe that would be the answer.